def document_it(func):
    def new_function(*args,**kwargs):
        print('Running function:',func.__name__)
        print('Positional arguments:', args)
        print('leword argument:',kwargs)
        result = func(*args,**kwargs)
        print('Result:',result)
        return result
    return new_function
 def square_it(func):
    def new_function(*arg,**kwargs):
        result= func(*arg,**kwargs)
        return result*result
    return new_function
//執行1
@document_it
@square_it
def add_ints(a,b):
    return a+b
add_ints(3,5)
//執行2
@square_it
@document_it
def add_ints(a,b):
    return a+b
add_ints(3,5)

執行1結果
Running function: new_function
Positional arguments: (3, 5)
leword argument: {}
Result: 64
64
執行2結果
Running function: add_ints
Positional arguments: (3, 5)
leword argument: {}
Result: 8
64

一直搞不懂為何@document_it和@square_it執行順序對調結果會不一樣
我的想法是對調不會有差別,執行解果都長這樣。
Running function: new_function
Positional arguments: (3, 5)
leword argument: {}
Result: 8
8
64
小弟剛接觸python問的 問題很粗淺還請多包涵