Python讀取json檔後找尋符合條件的字串並輸出

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vivian881118 2019-07-23 15:14:02 ‧ 5703 瀏覽

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Python讀取json檔後找尋符合條件的字串並輸出所屬group
例如需要找到SmoothScroll這個字串並輸出為 group 1，目前有試過使用
for F in data:
if F=='SmoothScroll':
print('Group 1')
break
else:
print("no")!
但無法達到所要的需求，有進行爬文但沒有搜尋到方法，還請各位大大指點
以下是json檔

{'group 1': [{'index': 8,
   'API name': 'RegOpenKey',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop'},
   'action': 'Read'},
  {'index': 9,
   'API name': 'RegQueryValue',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop\\SmoothScroll'},
   'action': 'Read'},
  {'index': 10,
   'API name': 'RegCloseKey',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop'},
   'action': 'Close'},
  {'index': 54,
   'API name': 'RegOpenKey',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop'},
   'action': 'Read'},
  {'index': 55,
   'API name': 'RegQueryValue',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop\\SmoothScroll'},
   'action': 'Read'},
  {'index': 56,
   'API name': 'RegCloseKey',
   'params': {'hKey': 'HKEY_CURRENT_USER\\Control Panel\\Desktop'},
   'action': 'Close'}]}

froce iT邦大師 1 級 ‧ 2019-07-23 15:16:25 檢舉

丟個測試的json上來，麻煩用code block...
這個要用filter才好做。

vivian881118 iT邦新手 5 級 ‧ 2019-07-23 15:38:11 檢舉

不好意思請問這樣放可以嗎

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1 個回答

froce

iT邦大師 1 級 ‧ 2019-07-23 16:35:31

最佳解答

import json

json_str = r"""
{
	"group 1": [{
			"index": 8,
			"API name": "RegOpenKey",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop"
			},
			"action": "Read"
		},
		{
			"index": 9,
			"API name": "RegQueryValue",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop\\SmoothScroll"
			},
			"action": "Read"
		},
		{
			"index": 10,
			"API name": "RegCloseKey",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop"
			},
			"action": "Close"
		},
		{
			"index": 54,
			"API name": "RegOpenKey",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop"
			},
			"action": "Read"
		},
		{
			"index": 55,
			"API name": "RegQueryValue",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop\\SmoothScroll"
			},
			"action": "Read"
		},
		{
			"index": 56,
			"API name": "RegCloseKey",
			"params": {
				"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop"
			},
			"action": "Close"
		}
	],
	"group 2": [{
		"index": 8,
		"API name": "RegOpenKey",
		"params": {
			"hKey": "HKEY_CURRENT_USER\\Control Panel\\Desktop"
		},
		"action": "Read"
	}]
}"""

data = json.loads(json_str)

def haveKeyWord(l, keyword):
	_ = list(filter(lambda x: keyword in x['params']['hKey'].split("\\"), l))
	return True if _ else False

result = dict(filter(lambda x:haveKeyWord(x[1], "SmoothScroll"), data.items()))

print(result.keys())

https://ideone.com/45SQL0

幫你改了JSON，並且多加了一組測試的 group 2