請教大神使用Django架站，報錯誤type error

python django 新手上路

to790303 2019-07-28 15:19:59 ‧ 2992 瀏覽

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各位大神午安，目前正在使用django架設練習網頁，在設置Django urls name一直發生錯誤，請問有無熟悉django的大神可以給點方向!

以下是我的程式碼
urls.py

from django.contrib import admin
from django.urls import path

from . import views

urlpatterns = [
    path('', views.showtemplate),
    path('<int:id>/', views.singleVendor, name='vendor_id'), # 這一行
    path('create', views.vendor_create_view),
]`

views.py

from django.shortcuts import render
from .models import Vendor
from .forms import VendorForm #import相對應的model Form
from .forms import RawVendorForm # 新增 RawVendorForm
from django.http import Http404
from django.shortcuts import get_object_or_404

# Create your views here.
def showtemplate(request):
    vendor_list = Vendor.objects.all() # 把所有 Vendor 的資料取出來
    context = {'vendor_list': vendor_list} # 建立 Dict對應到Vendor的資料，
    return render(request, 'vendors/vendor_detail.html', context)
#建立class [vendor_create_view]
def vendor_create_view(request):
    form = RawVendorForm(request.POST or None)
    if form.is_valid():
        Vendor.objects.create(**form.cleaned_data)
        form = RawVendorForm()
    context = {
        'form' : form
    }
    return render(request, "vendors/vendor_create.html", context)
def singleVendor(request, id):
    vendor_list = get_object_or_404(Vendor, id=id)
    # try:
    #     vendor_list = Vendor.objects.get(id=id)
    # except Vendor.DoesNotExist:
    #     raise Http404
    context = {
        'vendor_list': vendor_list
    }
    return render(request, 'vendors/vendor_detail.html', context)

modles.py

from django.db import models
# 新增
from django.contrib import admin
# 額外 import 這個過濾套件
from django.utils.translation import gettext_lazy as _
from django.urls import reverse #新增

# Create your models here.
class Vendor(models.Model):
	vendor_name = models.CharField(max_length = 20) # 攤販的名稱
	store_name = models.CharField(max_length = 10) # 攤販店家的名稱
	phone_number = models.CharField(max_length = 20) # 攤販的電話號碼
	address = models.CharField(max_length = 100) # 攤販的地址
     #新增
	def get_absolute_url(self):
		return reverse("vendor_id", kwargs={"id": self.id})

vedor_detail.html

<!DOCTYPE html>
<html lang="en" dir="ltr">
  <head>
    <meta charset="utf-8">
    <title></title>
  </head>
  <body>
{% extends "base.html" %}
{% block title %} My store {% endblock %}
{% block content%}
{% for vlist in vendor_list %}
  <h1> 店家 : {{vlist.vendor_name}} </h1>
  <p> <a href= {{ vlist.get_absolute_url }}> More detail...</a> </p>
{% endfor %}
{% endblock %}
  </body>
</html>

錯誤原因:TypeError at /vendor/1/
'Vendor' object is not iterable
Request Method: GET
Request URL: http://127.0.0.1:8000/vendor/1/
Django Version: 2.2.3
Exception Type: TypeError
Exception Value:
'Vendor' object is not iterable

有google過錯誤原因，試著修改vedor_detail，還是會顯示失敗，請各位大神幫幫忙

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1 個回答

froce

iT邦大師 1 級 ‧ 2019-07-28 19:52:58

最佳解答

vendor_list = get_object_or_404(Vendor, id=id)

這樣你得到的不會是 query set，而是單一的model物件。

{% for vlist in vendor_list %}
  <h1> 店家 : {{vlist.vendor_name}} </h1>
  <p> <a href= {{ vlist.get_absolute_url }}> More detail...</a> </p>
{% endfor %}

然後你拿來迭代，當然會跳錯誤。