如題，
運行程式碼後得到以下錯誤訊息
有上網找過解決方法，但是都沒有用
https://teamtreehouse.com/community/rangeerror-invalid-status-code-undefined-when-linking-to-another-page
https://reviewdb.io/questions/1537629072146/getting-rangeerror-err_http_invalid_status_code-invalid-status-code-3
以下是POST過去的DATA
{"pname" : "book"}
懇請各位大大解答，感謝
已邀請的邦友 {{ invite_list.length }}/5
雖然已經沒問題了
這個就當參考吧 
const Express = require('express');
const axios = require('axios');
const cheerio = require('cheerio');
const app = Express();
const router = Express.Router();
const port = 9999;
router.get('/search/:keyword', async (req, res) => {
await crawlPage(req.params.keyword)
.then(result => res.status(200).send({ keyword: req.params.keyword, result }).end())
.catch((err) => {
console.log(err);
res.status(500).send({ message: err }).end()
});
});
const crawlPage = (keyword) => {
return new Promise((resolve, reject) => {
const baseUrl = 'https://www.google.com/search';
const query = {
// ei: 'at5DXeq3H8SSr7wPzc-56AU',
q: keyword,
// oq: 'it邦幫忙',
// gs_l: 'psy-ab.3..0l9j0i7i30.2043.2043..3196...0.0..0.52.52.1......0....1..gws-wiz.h4Uim--P2-c',
// ved: '0ahUKEwjqlLPEzePjAhVEyYsBHc1nDl0Q4dUDCAo',
// uact: 5
};
const options = {
headers: {
'accept-language': ' zh-TW,zh;q=0.9,en-US;q=0.8,en;q=0.7',
'user-agent': ' Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.142 Safari/537.36',
}
};
const searchUrl = new URL(baseUrl);
const searchQuery = new URLSearchParams(query);
searchUrl.search = searchQuery;
axios.get(searchUrl.href, options)
.then((res) => {
const $ = cheerio.load(res.data);
resolve($('#resultStats').text());
})
.catch(err => reject(err));
});
};
app.use(router);
app.listen(port, () => {
console.log(`Server is listening at http://127.0.0.1:${port}`);
});
網址輸入
http://127.0.0.1:9999/search/${要搜尋的關鍵字}
e.g.
http://127.0.0.1:9999/search/it邦幫忙
就可以拿到結果
{
keyword: "it邦幫忙",
result: "約有 1,140,000 項結果 (搜尋時間：0.27 秒) "
}
大大你好，我換了一個寫法
crawler.js
const axios = require('axios');
const cheerio = require('cheerio'); //用 cheerio 擷取我們頁面要的部份
//crawler
const crawlPage = (pname) => {
const baseUrl = 'https://www.google.com/search';
const query = {
q: pname
};
const options = {
headers: {
'accept-language': ' zh-TW,zh;q=0.9,en-US;q=0.8,en;q=0.7',
'user-agent': ' Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.142 Safari/537.36',
}
};
const searchUrl = new URL(baseUrl);
const searchQuery = new URLSearchParams(query);
searchUrl.search = searchQuery;
axios.get(searchUrl.href, options)
.then((res) => {
var $ = cheerio.load(res.data);
console.log($('#resultStats').text());
const total_number = $('#resultStats').text().substring($('#resultStats').text().indexOf("有")+2,$('#resultStats').text().indexOf("項")-1).split(",").join("");
return total_number;
}).catch(err => console.log(err));
};
module.exports = {crawlPage};
app.js
const crawler = require("./crawler");
//create
app.post('/',(req,res,next)=>{
// Document to be inserted
const pname = req.body.pname;
console.log(pname+"pname");
const total_number = crawler.crawlPage(pname);
console.log(total_number+"total_number");
const obj = { pname : pname , total_number : total_number };
// insert document within collection
db.getDB().collection(collection).insertOne(obj,(err,result)=>{
if(err){
const error = new Error("Failed to insert Document");
res.status = 400;
next(error);
}
else
{
//res.json({result : result, document : result.ops[0],msg : "Successfully inserted!!!",error : null});
console.log(result+'Successfully inserted');
}
});
});
這樣total_number收到的是undefined (இ﹏இ`｡)
函式好像最後才會跳到
axios.get(searchUrl.href, options)此函示執行
請問一定要使用promise中的非同步寫法嗎
對
不然 total_number 不會等你的 crawlPage
執行完成才往下走
大大不好意思，再打擾您，
app.js
router.post('/', async (req, res) => {
await crawlPage(req.body.pname)
.then( total_number =>
const obj = { pname : req.body.pname, total_number };
db.getDB().collection(collection).insertOne(obj,(err,result)=>{
if(err){
const error = new Error("Failed to insert Document");
res.status = 400;
next(error);
}
else
{
//res.json({result : result, document : result.ops[0],msg : "Successfully inserted!!!",error : null});
console.log(result+'Successfully inserted');
}
}
)
.catch((err) => {
console.log(err);
res.status(500).send({ message: err }).end()
});
});
我想直接在裡面的json資料存進mongoDB裡面，可是不知道為什麼這樣寫不行 QQ ...
有錯誤嗎
他會有
SyntaxError: Unexpected token const
抱歉初學JS不太會 ...
你要用 括號刮起來
如果後面不是單純 return 的話
.then((total_number) => { ... })
另外
我比較喜歡用 monk 來連 mongodb
const Express = require('express');
const axios = require('axios');
const cheerio = require('cheerio');
const app = Express();
const monk = require('monk');
const router = Express.Router();
const port = 9999;
const db = monk('127.0.0.1:27017/demo');
router.get('/search/:keyword', async (req, res) => {
const collection = db.get('demo1');
const result = await crawlPage(req.params.keyword)
.then(result => result)
.catch(err => res.status(500).send({ message: err }).end());
await collection.insert({ keyword: req.params.keyword, result });
res.status(200).send({ keyword: req.params.keyword, result }).end();
});
database
/* 1 */
{
"_id" : ObjectId("5d4546bf2bdb56242498c06d"),
"keyword" : "it邦幫忙",
"result" : "約有 1,140,000 項結果 (搜尋時間：0.26 秒) "
}
/* 2 */
{
"_id" : ObjectId("5d45478d80689222488a62c9"),
"keyword" : "youtube",
"result" : "約有 11,180,000,000 項結果 (搜尋時間：0.53 秒) "
}
感謝大大您的指點與幫忙，monk package讓程式碼簡潔很多，多謝推薦! ฅ•ω•ฅ
iThome鐵人賽
看影片追技術