如題,懇請各位大大解答,謝謝

Question data format
[{ id: 0, name: "temp0", option: ["A", "B"] }, { id: 1, name: "temp1", option: ["A", "C"] }]

 const mysqlQuery = () => {
        return new Promise((resolve) => {
            question.map(x => {
                mysqldb.query(sql, (err, rows, fields) => {
                    if (!err) {
                        x.totalQCount = rows[0].NumberOfQ //add new attribute and value
                        console.log(x.totalQCount) //display the value
                        console.log(x) //But not display new attribute and value
                        resolve(rows)
                    }
                })//end mysql query
            })//end for
        })
    } //end Promise
} //end for
 await mysqlQuery();

另外的版本也無法運行

for (let i = 0; i < question.length; i++) {
  
    const mysqlQuery = () => {
        return new Promise((resolve) => {
            mysqldb.query("select COUNT(UID) AS NumberOfQ FROM AnswerState where QID =?", [question[i]._id.toString()], (err, rows, fields) => {
         
                if (!err) {
                    // console.log(rows);
                    // question[i].totalQCount = rows[0].NumberOfQ
              
                    temp = rows[0].NumberOfQ
                    resolve(rows)
                } else {
                    console.log(err);
                }
            })//end mysql query
        })
    } //end Promise
    await mysqlQuery()
    question[i].totalQCount = 123

    console.log(question[i].totalQCount)
    console.log(question) // 一樣沒有增加新屬性與新值
}//end for