Laravel9 的 PHPUnit 無法對 GuzzleHttp\Client Mock

php phpunit laravel

企鵝大叔 2022-09-29 10:18:01 ‧ 862 瀏覽

分享至

test

class test_api_getToken()
{
    $this->mock(\GuzzleHttp\Client::class);
    $api_class = $this->app->make(\App\ApiClass::class);
}

class

class ApiClass
{
    private $guzzle;
    
    public function __construct()
    {
        dd(
            get_class(app(Client::class)),
            get_class(app(Client::class, ['config' => ['verify' => false]]))
        );
        /**
         *    Mockery_0_GuzzleHttp_Client
         *    GuzzleHttp\Client
         */
    }
}

想請教怎麼樣才能置換到第二個Client

登入發表討論

直播研討會

{{ item.channelVendor }} {{ item.webinarstarted }} |

直播中

1 個回答

woeichern

iT邦新手 1 級 ‧ 2022-09-29 23:21:41

應該是要用依賴注的方式：

class


user GuzzleHttp\Client;

class CpsService
{
    private $guzzle1;
    private $guzzle2;
    
    public function __construct(Client $guzzle1, Client $guzzle2)
    {
        $this->guzzle1 = $guzzle1;
        $this->guzzle2 = $guzzle2;
    }
}

test

class test_api_getToken()
{
    $client = new Client();
    $client2 = new Client(['config' => ['verify' => false]]);
    $service = new CpsService($client1, $client2);
    
    // 下略
}