Java的Regex套件似乎只能跑迴圈一筆筆累加符合條件的片段。

int from = 0;
int count = 0;
while(matcher.find(from)) {
        count++;
        from = matcher.start() + 1;
 }

若用Lambda就一個陳述搞定

import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.util.stream.Stream;
public class Test1 {
    public static void main(String[] args) throws Exception {
        String str = "\n" +
                "Starting copy...\n" +
                "SQLState = 22001, NativeError = 0" +
                "Error = [Microsoft][ODBC Driver 17 for SQL Server]String data, right truncation" +
                "SQLState = 22001, NativeError = 0" +
                "Error = [Microsoft][ODBC Driver 17 for SQL Server]String data, right truncation" +
                "" +
                "28 rows copied." +
                "Network packet size (bytes): 4096" +
                "Clock Time (ms.) Total     : 51     Average : (549.0 rows per sec.)";
        Pattern failPattern = Pattern.compile("right truncation");
        Matcher failMatcher = failPattern.matcher(str);
        System.out.println(Stream.iterate(0, i -> i + 1)
                .filter(i -> !failMatcher.find())
                .findFirst()
                .get());
     }
 }

得到結果是2，主要是Stream.iterate(0, i -> i + 1).filter(i -> !failMatcher.find()).findFirst().get();這個陳述，但可讀性好像不及規規矩矩的寫迴圈