各位大大好:

ajax 將資料用php寫回資料庫，並呈現在網頁上(呈現出來的資料沒問題)，但console.log會出現下列問題

若將i改成0會出現，console.log就會正常，但我是想要用將全部的陣列顯示在網頁上，所以將變數改為i。

想問各位大大有無方法，謝謝!

 	for(i=0;i<=a;i++){
        document.getElementById(bdate).innerHTML +='<h id="'+obj.show[0].num+'" onclick="showblock(this)">•'+obj.show[0].timest+' '+obj.show[0].class+'<br></h>';  }

$.ajax({
    
    type: "POST",
    url: "writeback.php",
    async:false,
    data: {
        "lab":lab,
        "bdate":bdate,
        "clr":clr,
        "timest":timest,
        "timeov":timeov,
        "mdata":mdata,
            },
    success: function(info) {
      $("#cca").fadeOut(4000);
        var obj=JSON.parse(info);
        console.log(obj);
         var a=obj.length;
         var i=0;
        $("#" + bdate).find("h").each(function(){
           $(this).remove();
           });
             if(a<6){
             	
             	for(i=0;i<=a;i++){
        document.getElementById(bdate).innerHTML +='<h id="'+obj.show[i].num+'" onclick="showblock(this)">•'+obj.show[i].timest+' '+obj.show[i].class+'<br></h>';  }
        }
    }
  

});

});

}

writeback.php

$sql3="select * from ".$mdata." where bdate= :bdate order by timest asc";
$sql4 =$conn->prepare($sql3);
$ar_val=array('bdate'=>$bdate);
if($sql4->execute($ar_val)){
$show=[];
while($row=$sql4->fetch())
{
$show[] = array('timest'=>$row['timest'],'class'=>$row['clr'],'num'=>$row['識別碼'],'keynum'=>$row['keynum'],'keyturn'=>$row['keyturn']);	
}
}

$sql5="select * from ".$mdata." where bdate= :bdate order by timest asc";
$sql6 =$conn->prepare($sql5);
$ar_val3=array('bdate'=>$bdate);
if($sql6->execute($ar_val3))
{


while($row1=$sql6->fetchAll())
{
$numm=count($row1);

}


echo json_encode(array('show'=>$show,'length'=>$numm),JSON_UNESCAPED_UNICODE);


}

$conn=null; //結束對象資源
}