玩玩SQL~查詢當月排班各區間的班別~SQL改善完成!

sql t-sql

純真的人 2024-10-13 11:19:30 ‧ 3276 瀏覽

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恩~遇到一個不知道如何用純SQL寫法的當月排班班別區間

只能想到用T-SQL來達成寫法...

先給前置資料的SQL

declare @Shift table(
	Name nvarchar(20)
	,SetDate date
	,Code nvarchar(5)
)
insert into @Shift
values('小明','2024/10/1','A'),('小明','2024/10/2','A'),('小明','2024/10/3','A'),('小明','2024/10/4','A')
,('小明','2024/10/5','休'),('小明','2024/10/6','休'),('小明','2024/10/7','A'),('小明','2024/10/8','A')
,('小明','2024/10/9','A'),('小明','2024/10/10','休'),('小明','2024/10/11','A'),('小明','2024/10/12','休')
,('小明','2024/10/13','休'),('小明','2024/10/14','B'),('小明','2024/10/15','B'),('小明','2024/10/16','B')
,('小明','2024/10/17','B'),('小明','2024/10/18','B'),('小明','2024/10/19','休'),('小明','2024/10/20','休')
,('小明','2024/10/21','A'),('小明','2024/10/22','A'),('小明','2024/10/23','A'),('小明','2024/10/24','A')
,('小明','2024/10/25','A'),('小明','2024/10/26','休'),('小明','2024/10/27','休'),('小明','2024/10/28','A')
,('小明','2024/10/29','A'),('小明','2024/10/30','A'),('小明','2024/10/31','A')
,('大白','2024/10/1','特'),('大白','2024/10/2','特'),('大白','2024/10/3','B'),('大白','2024/10/4','B')
,('大白','2024/10/5','休'),('大白','2024/10/6','休'),('大白','2024/10/7','B'),('大白','2024/10/8','B')
,('大白','2024/10/9','B'),('大白','2024/10/10','休'),('大白','2024/10/11','B'),('大白','2024/10/12','休')
,('大白','2024/10/13','休'),('大白','2024/10/14','A'),('大白','2024/10/15','A'),('大白','2024/10/16','A')
,('大白','2024/10/17','A'),('大白','2024/10/18','A'),('大白','2024/10/19','休'),('大白','2024/10/20','休')
,('大白','2024/10/21','B'),('大白','2024/10/22','B'),('大白','2024/10/23','B'),('大白','2024/10/24','B')
,('大白','2024/10/25','B'),('大白','2024/10/26','休'),('大白','2024/10/27','休'),('大白','2024/10/28','B')
,('大白','2024/10/29','B'),('大白','2024/10/30','B'),('大白','2024/10/31','B')

--A代表 08-16 早班時段
--B代表 13-21 午班時段

--想要的結果： 
--大白 , B:1~13、A:14~20、B:21~31
--小明 , A:1~13、B:14~20、A:21~31

我用T-SQL後，得到此結果~

看有哪位高手比較厲害的SQL寫法...^^

我再分享我寫的T-SQL

好像我表達的不好~我貼出T-SQL好了~看如何改善成為純SQL

我也把直轉橫列出~比較看得懂..

select *
from (
	select Name
	,day(SetDate) DayNum
	,Code
	from @Shift
) k
pivot (
	max(Code)
	for DayNum in(
		[1],[2],[3],[4],[5],[6],[7],[8],[9],[10]
		,[11],[12],[13],[14],[15],[16],[17],[18]
		,[19],[20],[21],[22],[23],[24],[25],[26]
		,[27],[28],[29],[30],[31]
	)
) p

T-SQL語法的寫法....0.0

declare @ShiftMonth table(
	Name nvarchar(20)
	,MonthCode nvarchar(max)
)

declare @ShiftName table(
	Sort int
	,Name nvarchar(20)
)

declare @ShiftSet table(
	Name nvarchar(20)
	,SetDate date
	,Code nvarchar(5)
	,LastDate date
	,LastCode nvarchar(5)
)

declare @Count int = 0
declare @Code nvarchar(5) = ''
declare @LastCode nvarchar(5) = ''
declare @StartDate date,@EndDate date
declare @UpdStartDate date,@UpdEndDate date
declare @i int = 0,@n int=0
declare @MonthCode nvarchar(max) = ''
declare @MonthStart date = '2024/10/1'
declare @MonthEnd date = dateadd(day,-1,dateadd(month,1,@MonthStart))

insert into @ShiftName
select Row_Number()Over(order by Name) Sort
,Name
from @Shift
where SetDate between @MonthStart and @MonthEnd
group by Name

declare @NameCount int = isNull((select count(0) from @ShiftName),0)
declare @Name nvarchar(20)
declare @k int = 0

while(@k<@NameCount)
begin
	set @k = @k + 1
	select @Name=Name
	from @ShiftName
	where Sort = @k

	insert into @ShiftSet
	select *
	,isNull((
		select top 1 b.SetDate
		from @Shift b
		where a.Name = b.Name
		and Code not in('休','特')
		and a.SetDate < b.SetDate
	),a.SetDate) LastDay
	,isNull((
		select top 1 b.Code
		from @Shift b
		where a.Name = b.Name
		and Code not in('休','特')
		and a.SetDate < b.SetDate
	),a.Code) LastCode
	from @Shift a
	where Code not in('休','特')
	and Name = @Name

	set @i = 0
	set @n = 0
	set @Count = isNull((select count(0) from @ShiftSet),0)
	set @MonthCode = ''

	set @StartDate = @MonthStart

	while(@i<@Count)
	begin
		set @i = @i + 1

		if(@i=1)
		begin
			select top 1 @EndDate=LastDate
			,@Code=Code
			,@LastCode=LastCode
			from @ShiftSet
			order by SetDate
		end

		select @UpdStartDate=SetDate
		,@UpdEndDate=dateadd(day,-1,LastDate)
		,@Code=Code
		,@LastCode=LastCode
		from (
			select Row_Number()Over(order by SetDate) Sort
			,*
			from @ShiftSet
		) k
		where Sort = @i
		and Code<>LastCode

		if(@Code<>@LastCode)
		begin
			set @n = @n + 1
			set @EndDate = @UpdEndDate
			if(@MonthCode='')
			begin
				set @MonthCode = Convert(varchar,@Code) + ':' + Convert(varchar,Day(@StartDate)) + '~' + Convert(varchar,Day(@EndDate))
			end
			else
			begin
				set @MonthCode = @MonthCode + ',' + Convert(varchar,@Code) + ':' + Convert(varchar,Day(@StartDate)) + '~' + Convert(varchar,Day(@EndDate))
			end
			set @StartDate = dateadd(day,1,@EndDate)
			set @Code = @LastCode
		end
	end

	if(@Count>0)
	begin
		select @EndDate=max(SetDate)
		from @Shift
		where Name = @Name

		if(@MonthCode='')
		begin
			set @MonthCode = Convert(varchar,@Code) + ':' + Convert(varchar,Day(@StartDate)) + '~' + Convert(varchar,Day(@EndDate))
		end
		else
		begin
			set @MonthCode = @MonthCode + ',' + Convert(varchar,@Code) + ':' + Convert(varchar,Day(@StartDate)) + '~' + Convert(varchar,Day(@EndDate))
		end

		insert into @ShiftMonth 
		select @Name
		,@MonthCode

		delete from @ShiftSet
	end


end

select *
from @ShiftMonth

10/14號更新

謝謝一級屠豬士用 WITH 方式提醒
原來 WITH 的用法，是會繼承上個資料表的查詢，生成獨立的資料表
謝謝 rogeryao、pilipala 想法，將排班的班別改為連續班別，會比較簡單判斷
由其知道 2022 有個新函數【IGNORE NULLS】更簡單應用填入班別

我這個SQL版本比較舊是2016版本，有些新函數不能使用~只能寫比較多SQL來查詢了@@..

經改善的SQL如下，謝謝三位高手的指導~

WITH
NewShift as (
	select Name
	,SetDate
	,isNull((
		select top 1 b.Code
		from @Shift b
		where a.Name = b.Name
		and b.Code not in(N'特',N'休')
		and a.SetDate >= b.SetDate
		order by b.SetDate desc
	),(
		select top 1 b.Code
		from @Shift b
		where a.Name = b.Name
		and b.Code not in(N'特',N'休')
		and a.SetDate < b.SetDate
		order by b.SetDate desc
	)) Code
	from @Shift a
)
,CTE01 AS (
	SELECT M.Name,M.SetDate,M.Code
	,1 + SUM(M.Num) OVER (PARTITION BY M.Name ORDER BY M.SetDate) AS No
	FROM (
		SELECT NewShift.*,
			CASE WHEN Code = LAG(Code,1,Code) OVER (PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM NewShift
	) M
)
,CTE02 AS (
	SELECT Name,Code,No
	,Min(SetDate) AS MinDate
	,Max(SetDate) AS MaxDate
	FROM CTE01
	GROUP BY Name,Code,No
)
,CTE03 AS (
	SELECT Name,No,Code
	,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE02
)

SELECT Name
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.Name = b.Name
	order by no
	for xml path('')
),1,1,'') as AllStr
--,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE03 a
GROUP BY Name

謝謝 rogeryao 再次測試
國外網站 db<>fiddle 測試，因為文化特性要補上 N 來修正語言問題

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一級屠豬士 iT邦大師 1 級 ‧ 2024-10-13 12:42:50 檢舉

不知道你是要怎樣處理,不知道邏輯,怎麼寫.

純真的人 iT邦大師 1 級 ‧ 2024-10-13 13:07:06 檢舉

邏輯：假如10月排班
小明 ,
排A班:1號到13號(含休假)、
排B班:14號~20號(含休假)、
排A班:21號~31號(含休假)

排班順序是按照日期大小排序的

其實就是把所有人當月排班狀態列出來@@...

rogeryao iT邦超人 7 級 ‧ 2024-10-13 16:12:34 檢舉

我還以為只有我看不懂

純真的人 iT邦大師 1 級 ‧ 2024-10-13 18:54:07 檢舉

哈~畢竟是實例~拿出來玩看看~
看有無高手解法有什麼厲害的寫法0.0a
可能我敘述題目方式~
邏輯有點不通吧@@...
但實際上~主管想知道
小明幾號到幾號上A班時段，還是B班時段...
雖然從排班表看的很清楚~
但是在列出出勤報表相關紀錄的時候~
會濃縮在一個欄位紀錄出來@@"

rogeryao iT邦超人 7 級 ‧ 2024-10-13 19:40:48 檢舉

若以第一張貼圖為結果的話
我的資料結構會跟你不一樣
Code ：只會填入 A ,B ,C, D, E
意思是該員工本來排定的班別

另外新增一個欄位
Holiday ：休 or 特
第二張圖只是當 Holiday 有值時將 Code 顯示成 Holiday
這樣問題就變得比較單純

不然你的第一張圖就應該顯示休 or 特是哪幾天
否則主管會以為該員工當天有上班

或許有一天你會碰到有兩條生產線
一條用 A , B
一條用 C , D , E
那麼你的 T-SQL 或許會更複雜

純真的人 iT邦大師 1 級 ‧ 2024-10-13 20:52:27 檢舉

恩~畢竟那個資料結構~是前人留下的遺產
他們也是用很久了~我也只能照現有結構去變化^^a
【休 or 特】有另外的報表欄位顯示，會顯示請假有哪些項目
特休 2d0h、事假 1d0h、病假 0d4h、補休 0d4h、生理假 0d4h...幾天等等
我那個報表欄位單純只看班別資料的~
所以這個看起來無法純SQL處理@@..
只能用T-SQL來硬幹了^.^a

出勤報表欄位會分開一些項目~
不會把當月班別、休假之類都擠在一起~
【當月班別】【當月請假】【之類等等...】

>>或許有一天你會碰到有兩條生產線
早就更複雜了~
他們A1 A2 A3 上班時間都會早1小時或晚1小時~
或者廚師上班 A4 時段是 08-13 很短的時長呢
只是都會通稱為A班時段~
所以像這種要求同一個名稱叫A班~
但因配合同事時間會有點差異~
畢竟系統還要抓他們上下班有無遲到會早退的計算呢~

rogeryao iT邦超人 7 級 ‧ 2024-10-13 21:31:33 檢舉

如果
SetDate date ,
Code nvarchar(5)

這兩個欄位分屬不同的 Table , 那也會簡單一些

純真的人 iT邦大師 1 級 ‧ 2024-10-13 21:33:51 檢舉

可以~你可以試試你的方式~寫寫看@@

rogeryao iT邦超人 7 級 ‧ 2024-10-14 12:33:21 檢舉

你 10/14號更新的 Code 放到 db<>fiddle 跑出來的結果,跟你的貼圖不一樣
https://dbfiddle.uk/7cCnSk9B

純真的人 iT邦大師 1 級 ‧ 2024-10-14 13:37:53 檢舉

我改好 Code 了~語言文化問題~
前面要加 N'特',N'休'
https://dbfiddle.uk/EbERhpVZ

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3 個回答

一級屠豬士

iT邦大師 1 級 ‧ 2024-10-13 20:59:25

最佳解答

按我前往

with t1 as (
select boy, sdate
     , case when code = '休' or  code = '特' then null
       else code
       end
  from it1013
), t2 as (
select *
     , sum(case when code is null then 0 else 1 end) over(order by boy, sdate) as code_grp
  from t1
), t3 as (
select boy, sdate
     , first_value(code) over(partition by code_grp order by sdate) as new_code
  from t2
), t4 as (
select boy, sdate, new_code
     , sum(case when new_code is null then 0 else 1 end) over(order by boy, sdate desc) as new_code_grp
  from t3
), t5 as (
select boy, sdate
     , first_value(new_code) over(partition by new_code_grp order by sdate desc) as new_code2
  from t4
), t6 as (
select boy, sdate
     , new_code2
     , lag(new_code2) over(partition by boy order by sdate) lagcode
  from t5
), t7 as (
select boy, sdate, new_code2 as code
     , case when new_code2 = 'A' and lagcode = 'B' then true
            when new_code2 = 'B' and lagcode = 'A' then true
            else false
       end as cut
  from t6
), t8 as (
select boy, sdate, code, date_part('day', sdate)::int as cutdate
  from t7
 where cut
    or date_part('day', sdate)::int = 1
), t9 as (
select boy, code, cutdate, coalesce(lead(cutdate) over (partition by boy order by sdate) - 1, 31) as enddate
  from t8
) , t10 as (
select boy
     , cutdate
     , code || ':' || cutdate::text || '~' || enddate::text as datestr
  from t9
)
select boy
     , string_agg(datestr, ',' order by cutdate)
  from t10
 group by boy;

result:

 boy  |       string_agg
------+------------------------
 大白 | B:1~13,A:14~20,B:21~31
 小明 | A:1~13,B:14~20,A:21~31
(2 rows)

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一級屠豬士 iT邦大師 1 級 ‧ 2024-10-13 21:12:14 檢舉

完整的應該是在 coalesce(lead(cutdate) over (partition by boy order by sdate) - 1, 31)
這裡的31 要用日期函數計算出當月的最後一天.
但是我們使用的DB 不同, 這對純真的人大大來說,小菜一碟,所以我就偷懶直接使用31了.

純真的人 iT邦大師 1 級 ‧ 2024-10-13 21:13:17 檢舉

挖~~SQL化厲害~

純真的人 iT邦大師 1 級 ‧ 2024-10-13 21:17:41 檢舉

用 with 這個的確應用~我還沒有熟練XD..

一級屠豬士 iT邦大師 1 級 ‧ 2024-10-13 21:24:35 檢舉

用 window function, sum(), first_value(), lag(), lead(), 組合拳.string_agg() 聚合.
先把休假變成 null
sum(), first_value() 來填充 null, 正向一次,反向一次(大白月初兩天), 然後lag(), 然後判斷差異,算出分切點日期,
然後再將分切點日期, lead 上去減一天得到每組的區間,
然後將區間變成 sdate~edate ,然後 string_agg 聚合起來.

純真的人 iT邦大師 1 級 ‧ 2024-10-13 22:27:03 檢舉

好的~我想想with如何應用~謝謝

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pilipala

iT邦研究生 5 級 ‧ 2024-10-13 21:05:47

正常流程應該是，理論班表 => 實際出勤班表 => 幫 HR 勾稽兩者異常之處，讓 HR 去釐清判斷是否合理

休假日前後是 A、B 班別時，有邏輯可以判斷是歸屬哪個班別嗎？

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純真的人 iT邦大師 1 級 ‧ 2024-10-13 21:16:24 檢舉

班別是若遇當月休假換班別~就歸屬前一個班別~
例如 10/13 休 14/14 換成A班
那麼 10/13 會往前抓到最後一天的班別若是B班~
那麼10/13就算B班薪資

但是像月初就特休就會往後抓班別來判斷

至於HR勾稽~他們輪班比較沒辦做吧~
因為他們要排下個月班時~
會一個組討論~哪天誰可以上班~誰有事休假~
過年是沒有休假的~用輪班處理(會給特別加班費)

我這個題目範例是用固定排班來敘述的~
不是用輪班比較麻煩輸入@@...

pilipala iT邦研究生 5 級 ‧ 2024-10-14 03:25:40 檢舉

Step1：把特、休字樣改成所屬班別，使用 SQL 2022 視窗函數新參數 IGNORE NULLS 來整理
Step2：連續日期、連續班別來判斷群組
Step3：產生對應需求的資料

; 
WITH T1 AS 
( 
	SELECT * ,
		IIF(Code IN ('A' , 'B') , Code , NULL) AS NewCode
	FROM @Shift
)
, T2 AS
(
	SELECT * ,
		COALESCE(
			NewCode ,
			LAG(NewCode) IGNORE NULLS OVER (PARTITION BY Name ORDER BY SetDate) ,
			LEAD(NewCode) IGNORE NULLS OVER (PARTITION BY Name ORDER BY SetDate)) AS GroupNO
	FROM T1
)
, T3 AS 
(
	SELECT 
		* ,
		DATEADD(
			d , 
			ROW_NUMBER() OVER (PARTITION BY Name , GroupNO ORDER BY SetDate) * -1 , 
			SetDate) AS GroupDate
	FROM T2
)
, T4 AS
(
	SELECT 
			T3.Name , 
			T3.GroupDate ,
			T3.GroupNO ,
			MIN(SetDate) AS MinDate ,
			T3.GroupNO + '：' + CAST(DAY(MIN(SetDate)) AS varchar(2)) + '~' + CAST(DAY(MAX(SetDate)) AS varchar(2)) AS CodeInfo
	FROM T3
	GROUP BY Name , GroupDate , GroupNO
)
SELECT
	Name ,
	STRING_AGG(CodeInfo , ' , ') WITHIN GROUP (ORDER BY MinDate)
FROM T4
GROUP BY Name

純真的人 iT邦大師 1 級 ‧ 2024-10-14 08:56:35 檢舉

喔~了解~
你採用的是刪除特、休，改為Null值
利用 SQL 2022新視窗函數 IGNORE NULLS 填滿上次日期的班別
再利用連續班別，算出區段~

我的SQL版本比較舊~
所以重點就是變成連續班別填滿，SQL就會比較簡單

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rogeryao

iT邦超人 7 級 ‧ 2024-10-13 23:24:33

Code : 只有班別代號，不含休假或特休

CREATE TABLE da (
Name nvarchar(20),
SetDate date,
Code nvarchar(5));

INSERT INTO da (Name, SetDate,Code) VALUES
(N'小明','2024/10/1','A'),(N'小明','2024/10/2','A'),(N'小明','2024/10/3','A'),(N'小明','2024/10/4','A')
,(N'小明','2024/10/5',N'A'),(N'小明','2024/10/6',N'A'),(N'小明','2024/10/7','A'),(N'小明','2024/10/8','A')
,(N'小明','2024/10/9','A'),(N'小明','2024/10/10',N'A'),(N'小明','2024/10/11','A'),(N'小明','2024/10/12',N'A')
,(N'小明','2024/10/13',N'A'),(N'小明','2024/10/14','B'),(N'小明','2024/10/15','B'),(N'小明','2024/10/16','B')
,(N'小明','2024/10/17','B'),(N'小明','2024/10/18','B'),(N'小明','2024/10/19',N'B'),(N'小明','2024/10/20',N'B')
,(N'小明','2024/10/21','A'),(N'小明','2024/10/22','A'),(N'小明','2024/10/23','A'),(N'小明','2024/10/24','A')
,(N'小明','2024/10/25','A'),(N'小明','2024/10/26',N'A'),(N'小明','2024/10/27',N'A'),(N'小明','2024/10/28','A')
,(N'小明','2024/10/29','A'),(N'小明','2024/10/30','A'),(N'小明','2024/10/31','A')
,(N'大白','2024/10/1',N'B'),(N'大白','2024/10/2',N'B'),(N'大白','2024/10/3','B'),(N'大白','2024/10/4','B')
,(N'大白','2024/10/5',N'B'),(N'大白','2024/10/6',N'B'),(N'大白','2024/10/7','B'),(N'大白','2024/10/8','B')
,(N'大白','2024/10/9','B'),(N'大白','2024/10/10',N'B'),(N'大白','2024/10/11','B'),(N'大白','2024/10/12',N'B')
,(N'大白','2024/10/13',N'B'),(N'大白','2024/10/14','A'),(N'大白','2024/10/15','A'),(N'大白','2024/10/16','A')
,(N'大白','2024/10/17','A'),(N'大白','2024/10/18','A'),(N'大白','2024/10/19',N'A'),(N'大白','2024/10/20',N'A')
,(N'大白','2024/10/21','B'),(N'大白','2024/10/22','B'),(N'大白','2024/10/23','B'),(N'大白','2024/10/24','B')
,(N'大白','2024/10/25','B'),(N'大白','2024/10/26',N'B'),(N'大白','2024/10/27',N'B'),(N'大白','2024/10/28','B')
,(N'大白','2024/10/29','B'),(N'大白','2024/10/30','B'),(N'大白','2024/10/31','B');

WITH CTE01 AS (SELECT M.Name,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name ORDER BY M.SetDate) AS No
FROM (
SELECT da.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM da) M),  
CTE02 AS (
SELECT Name,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE01
GROUP BY Name,Code,No),
CTE03 AS (
SELECT Name,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE02)

SELECT Name,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE03
GROUP BY Name

Demo

休假或特休

CREATE TABLE dc (
Name nvarchar(20),
SetDate date,
Holiday nvarchar(5));

INSERT INTO dc (Name, SetDate,Holiday) VALUES
(N'小明','2024/10/5',N'休'),
(N'小明','2024/10/6',N'休'),
(N'小明','2024/10/10',N'休'),
(N'小明','2024/10/12',N'休'),
(N'小明','2024/10/13',N'休'),
(N'小明','2024/10/19',N'休'),
(N'小明','2024/10/20',N'休'),
(N'小明','2024/10/26',N'休'),
(N'小明','2024/10/27',N'休'),
(N'大白','2024/10/1',N'特'),
(N'大白','2024/10/2',N'特'),
(N'大白','2024/10/5',N'休'),
(N'大白','2024/10/6',N'休'),
(N'大白','2024/10/10',N'休'),
(N'大白','2024/10/12',N'休'),
(N'大白','2024/10/13',N'休'),
(N'大白','2024/10/19',N'休'),
(N'大白','2024/10/20',N'休'),
(N'大白','2024/10/26',N'休'),
(N'大白','2024/10/27',N'休');

SELECT F.Name,F.SetDate,F.Holiday,1 + SUM(F.HNum) OVER (
PARTITION BY F.Name ORDER BY F.SetDate) AS HNo
FROM (
SELECT dc.*,
CASE WHEN Holiday = LAG(Holiday,1,Holiday) OVER (
PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS HNum
FROM dc) F

Demo
休假或特休 dc 與 da left join 應該可以產生出圖二，
此處 SQL 只便於找出休假或特休群組，不在贅述。

參考資料 : SQL 依時間排序連續資料的分組

Code 可以包含休、特的解法在底下回應區 :『修正版』

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純真的人 iT邦大師 1 級 ‧ 2024-10-14 00:05:35 檢舉

喔~
你採用沒有混合休假的排班~
純粹班別哪到哪~的確是很好查詢
休假有另外的資料表紀錄在混合進來~

可惜他們班表功能是這樣混合的

rogeryao iT邦超人 7 級 ‧ 2024-10-14 00:42:12 檢舉

班別是若遇當月休假換班別~就歸屬前一個班別~
例如 10/13 休 14/14 換成A班
那麼 10/13 會往前抓到最後一天的班別若是B班~
那麼10/13就算B班薪資

『那麼 10/13 會往前抓到最後一天的班別若是B班~』
其實,這樣的論述可能是有問題的
一般來說應該是先有排班表，不同的班別薪資也會不一樣
10/13 請假時排到什麼班表，就扣除那個班表的錢
而不是往前推最後一次有上班的班表
仔細算薪資會有差別

或許有一天會發生
10/13 往前推是 B 班
但是人事部門算薪資時是用 A 班計算

純真的人 iT邦大師 1 級 ‧ 2024-10-14 01:18:25 檢舉

這個就看人資訂下規則為準囉(通常會發公告，或者寫在員工手冊裡面)~
我們看他怎麼解釋~就怎樣設定了~

rogeryao iT邦超人 7 級 ‧ 2024-10-14 12:18:20 檢舉

Code 可以包含休、特

CREATE TABLE da (
Name nvarchar(20),
SetDate date,
Code nvarchar(5));

INSERT INTO da (Name, SetDate,Code) VALUES
(N'小明','2024/10/1','A'),(N'小明','2024/10/2','A'),(N'小明','2024/10/3','A'),(N'小明','2024/10/4','A')
,(N'小明','2024/10/5',N'休'),(N'小明','2024/10/6',N'休'),(N'小明','2024/10/7','A'),(N'小明','2024/10/8','A')
,(N'小明','2024/10/9','A'),(N'小明','2024/10/10',N'休'),(N'小明','2024/10/11','A'),(N'小明','2024/10/12',N'休')
,(N'小明','2024/10/13',N'休'),(N'小明','2024/10/14','B'),(N'小明','2024/10/15','B'),(N'小明','2024/10/16','B')
,(N'小明','2024/10/17','B'),(N'小明','2024/10/18','B'),(N'小明','2024/10/19',N'休'),(N'小明','2024/10/20',N'休')
,(N'小明','2024/10/21','A'),(N'小明','2024/10/22','A'),(N'小明','2024/10/23','A'),(N'小明','2024/10/24','A')
,(N'小明','2024/10/25','A'),(N'小明','2024/10/26',N'休'),(N'小明','2024/10/27',N'休'),(N'小明','2024/10/28','A')
,(N'小明','2024/10/29','A'),(N'小明','2024/10/30','A'),(N'小明','2024/10/31','A')
,(N'大白','2024/10/1',N'特'),(N'大白','2024/10/2',N'特'),(N'大白','2024/10/3','B'),(N'大白','2024/10/4','B')
,(N'大白','2024/10/5',N'休'),(N'大白','2024/10/6',N'休'),(N'大白','2024/10/7','B'),(N'大白','2024/10/8','B')
,(N'大白','2024/10/9','B'),(N'大白','2024/10/10',N'休'),(N'大白','2024/10/11','B'),(N'大白','2024/10/12',N'休')
,(N'大白','2024/10/13',N'休'),(N'大白','2024/10/14','A'),(N'大白','2024/10/15','A'),(N'大白','2024/10/16','A')
,(N'大白','2024/10/17','A'),(N'大白','2024/10/18','A'),(N'大白','2024/10/19',N'休'),(N'大白','2024/10/20',N'休')
,(N'大白','2024/10/21','B'),(N'大白','2024/10/22','B'),(N'大白','2024/10/23','B'),(N'大白','2024/10/24','B')
,(N'大白','2024/10/25','B'),(N'大白','2024/10/26',N'休'),(N'大白','2024/10/27',N'休'),(N'大白','2024/10/28','B')
,(N'大白','2024/10/29','B'),(N'大白','2024/10/30','B'),(N'大白','2024/10/31','B');

-- 每月 1 日'休'、'特', 找到第一個班別向上補
WITH CTE01 AS (
SELECT da.Name,da.SetDate,
CASE WHEN da.SetDate < K.SetDate THEN K.Code ELSE da.Code END AS Code
FROM da
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS RN,*
FROM da
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=da.Name),
-- 向下補班別  
CTE02 AS (
SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS id,
Name,SetDate,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT id,Name,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT id,Name,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (SELECT M.Name,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,Code,No),
CTE06 AS (
SELECT Name,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)

SELECT Name,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name

Demo

Demo:SQL 2016

Code 可以包含 休、特

```
CREATE TABLE da (
Name nvarchar(20),
SetDate date,
Code nvarchar(5));

INSERT INTO da (Name, SetDate,Code) VALUES
(N'小明','2024/10/1','A'),(N'小明','2024/10/2','A'),(N'小明','2024/10/3','A'),(N'小明','2024/10/4','A')
,(N'小明','2024/10/5',N'休'),(N'小明','2024/10/6',N'休'),(N'小明','2024/10/7','A'),(N'小明','2024/10/8','A')
,(N'小明','2024/10/9','A'),(N'小明','2024/10/10',N'休'),(N'小明','2024/10/11','A'),(N'小明','2024/10/12',N'休')
,(N'小明','2024/10/13',N'休'),(N'小明','2024/10/14','B'),(N'小明','2024/10/15','B'),(N'小明','2024/10/16','B')
,(N'小明','2024/10/17','B'),(N'小明','2024/10/18','B'),(N'小明','2024/10/19',N'休'),(N'小明','2024/10/20',N'休')
,(N'小明','2024/10/21','A'),(N'小明','2024/10/22','A'),(N'小明','2024/10/23','A'),(N'小明','2024/10/24','A')
,(N'小明','2024/10/25','A'),(N'小明','2024/10/26',N'休'),(N'小明','2024/10/27',N'休'),(N'小明','2024/10/28','A')
,(N'小明','2024/10/29','A'),(N'小明','2024/10/30','A'),(N'小明','2024/10/31','A')
,(N'大白','2024/10/1',N'特'),(N'大白','2024/10/2',N'特'),(N'大白','2024/10/3','B'),(N'大白','2024/10/4','B')
,(N'大白','2024/10/5',N'休'),(N'大白','2024/10/6',N'休'),(N'大白','2024/10/7','B'),(N'大白','2024/10/8','B')
,(N'大白','2024/10/9','B'),(N'大白','2024/10/10',N'休'),(N'大白','2024/10/11','B'),(N'大白','2024/10/12',N'休')
,(N'大白','2024/10/13',N'休'),(N'大白','2024/10/14','A'),(N'大白','2024/10/15','A'),(N'大白','2024/10/16','A')
,(N'大白','2024/10/17','A'),(N'大白','2024/10/18','A'),(N'大白','2024/10/19',N'休'),(N'大白','2024/10/20',N'休')
,(N'大白','2024/10/21','B'),(N'大白','2024/10/22','B'),(N'大白','2024/10/23','B'),(N'大白','2024/10/24','B')
,(N'大白','2024/10/25','B'),(N'大白','2024/10/26',N'休'),(N'大白','2024/10/27',N'休'),(N'大白','2024/10/28','B')
,(N'大白','2024/10/29','B'),(N'大白','2024/10/30','B'),(N'大白','2024/10/31','B');
```
```
-- 每月 1 日'休'、'特', 找到第一個班別向上補
WITH CTE01 AS (
SELECT da.Name,da.SetDate,
CASE WHEN da.SetDate < K.SetDate THEN K.Code ELSE da.Code END AS Code
FROM da
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS RN,*
FROM da
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=da.Name),
-- 向下補班別  
CTE02 AS (
SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS id,
Name,SetDate,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT id,Name,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT id,Name,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (SELECT M.Name,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,Code,No),
CTE06 AS (
SELECT Name,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)

SELECT Name,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name
```
[Demo](https://dbfiddle.uk/0_Iwm5vB)

[Demo:SQL 2016](https://dbfiddle.uk/0z7AEKcL)

修改

純真的人 iT邦大師 1 級 ‧ 2024-10-14 14:51:43 檢舉

收到 2016 新寫法了~謝謝!

純真的人 iT邦大師 1 級 ‧ 2024-10-15 09:25:15 檢舉

我今天測試你的寫法~(班別向上補及班別向下補)
left join效能比較好~
用子查詢的方式~跑1萬多筆很久快1分鐘都沒結果(我按中止)
用left join查詢，1萬多筆滿馬上就出現了^_^

rogeryao iT邦超人 7 級 ‧ 2024-10-15 10:14:54 檢舉

早上本想請你測試執行速度的差異
真是心有靈犀

純真的人 iT邦大師 1 級 ‧ 2024-10-15 10:23:11 檢舉

哈~畢竟改程式都有先後順序~
要等我有時間~才能空處理~

rogeryao iT邦超人 7 級 ‧ 2024-10-15 10:48:28 檢舉

你寫的這種『子查詢』方式
我幾乎不使用，都改用 LEFT JOIN 處理
直覺上他是針對每一筆下一道 SQL

你可以用 SQL Server Profiler 看看
2 個 SQL的差異

純真的人 iT邦大師 1 級 ‧ 2024-10-15 11:35:04 檢舉

子查詢其實弊端很大~
因為他是針對每一筆~
另開資料表總查詢~
所以跑很久~
LEFT JOIN 是先把總表處理好，在比對join有沒有而已~
因為他不是獨立去查詢的~所以會比較快

純真的人 iT邦大師 1 級 ‧ 2024-10-15 23:38:33 檢舉

今天有試了 WITH + 加上用你的

WITH
略....
LEFT JOIN (
   略......
)  AS K

跑了一個歷史打卡資料看看(4萬多筆)，結果跑了22秒...0.0a

後來想了一下~可能WITH會不斷遞迴關係~

我就移出 WITH 外面

用 declare @Tmp table 暫存一個資料表~1秒左右就跑完了@@...

declare @Tmp table
略....
insert into @Tmp
略....
LEFT JOIN (
   略......
)  AS K

WITH
略....

rogeryao iT邦超人 7 級 ‧ 2024-10-15 23:58:57 檢舉

可能WITH會不斷遞迴關係~

應該不會吧
WITH 只是把原本一大串的 SQL分段處理
就上面的 Case 而言也可以寫成一大串，但是可讀性就變差了，
除錯也會變得很困難

歷史打卡資料的問題或許跟上面的 Case 有些差異
但是你硬把 SQL 套進去
可能就會不如預期吧

rogeryao iT邦超人 7 級 ‧ 2024-10-16 01:00:47 檢舉

剛想到上面的 SQL 有個小瑕疵：

-- 向下補班別  
CTE02 AS (
SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS id,
CTE03 AS (
...
SELECT id,Name,SetDate,CodeX, 
... 
SELECT id,Name,SetDate,CodeX,
這個 id 是多餘的

另外，有個潛藏的問題

PARTITION BY Name 
應該要改成下式，要加入年月(2024-10)
PARTITION BY Name,Left(SetDate,7)
否則，當只查詢一個人而且跨月時會有問題。

原本是（小明、大白，10月）
大白 2024-10-01 特
大白 2024-10-02 特
取代休、特
大白 2024-10-01 B
大白 2024-10-02 B
................................................
當（大白，9～10月）
取代休、特會變成
大白 2024-10-01 A
大白 2024-10-02 A

A 是 9月延伸而產生的
Demo:問題示範

rogeryao iT邦超人 7 級 ‧ 2024-10-16 08:39:09 檢舉

『修正版』

CREATE TABLE da (
Name nvarchar(20),
SetDate date,
Code nvarchar(5));

INSERT INTO da (Name, SetDate,Code) VALUES
(N'大白','2024/09/1','A'),(N'大白','2024/09/2','A'),(N'大白','2024/09/3','A'),(N'大白','2024/09/4','A')
,(N'大白','2024/09/5',N'休'),(N'大白','2024/09/6',N'休'),(N'大白','2024/09/7','A'),(N'大白','2024/09/8','A')
,(N'大白','2024/09/9','A'),(N'大白','2024/09/10',N'休'),(N'大白','2024/09/11','A'),(N'大白','2024/09/12',N'休')
,(N'大白','2024/09/13',N'休'),(N'大白','2024/09/14','B'),(N'大白','2024/09/15','B'),(N'大白','2024/09/16','B')
,(N'大白','2024/09/17','B'),(N'大白','2024/09/18','B'),(N'大白','2024/09/19',N'休'),(N'大白','2024/09/20',N'休')
,(N'大白','2024/09/21','A'),(N'大白','2024/09/22','A'),(N'大白','2024/09/23','A'),(N'大白','2024/09/24','A')
,(N'大白','2024/09/25','A'),(N'大白','2024/09/26',N'休'),(N'大白','2024/09/27',N'休'),(N'大白','2024/09/28','A')
,(N'大白','2024/09/29','A'),(N'大白','2024/09/30','A')
,(N'大白','2024/10/1',N'特'),(N'大白','2024/10/2',N'特'),(N'大白','2024/10/3','B'),(N'大白','2024/10/4','B')
,(N'大白','2024/10/5',N'休'),(N'大白','2024/10/6',N'休'),(N'大白','2024/10/7','B'),(N'大白','2024/10/8','B')
,(N'大白','2024/10/9','B'),(N'大白','2024/10/10',N'休'),(N'大白','2024/10/11','B'),(N'大白','2024/10/12',N'休')
,(N'大白','2024/10/13',N'休'),(N'大白','2024/10/14','A'),(N'大白','2024/10/15','A'),(N'大白','2024/10/16','A')
,(N'大白','2024/10/17','A'),(N'大白','2024/10/18','A'),(N'大白','2024/10/19',N'休'),(N'大白','2024/10/20',N'休')
,(N'大白','2024/10/21','B'),(N'大白','2024/10/22','B'),(N'大白','2024/10/23','B'),(N'大白','2024/10/24','B')
,(N'大白','2024/10/25','B'),(N'大白','2024/10/26',N'休'),(N'大白','2024/10/27',N'休'),(N'大白','2024/10/28','B')
,(N'大白','2024/10/29','B'),(N'大白','2024/10/30','B'),(N'大白','2024/10/31','B')
,(N'小明','2024/10/1','A'),(N'小明','2024/10/2','A'),(N'小明','2024/10/3','A'),(N'小明','2024/10/4','A')
,(N'小明','2024/10/5',N'休'),(N'小明','2024/10/6',N'休'),(N'小明','2024/10/7','A'),(N'小明','2024/10/8','A')
,(N'小明','2024/10/9','A'),(N'小明','2024/10/10',N'休'),(N'小明','2024/10/11','A'),(N'小明','2024/10/12',N'休')
,(N'小明','2024/10/13',N'休'),(N'小明','2024/10/14','B'),(N'小明','2024/10/15','B'),(N'小明','2024/10/16','B')
,(N'小明','2024/10/17','B'),(N'小明','2024/10/18','B'),(N'小明','2024/10/19',N'休'),(N'小明','2024/10/20',N'休')
,(N'小明','2024/10/21','A'),(N'小明','2024/10/22','A'),(N'小明','2024/10/23','A'),(N'小明','2024/10/24','A')
,(N'小明','2024/10/25','A'),(N'小明','2024/10/26',N'休'),(N'小明','2024/10/27',N'休'),(N'小明','2024/10/28','A')
,(N'小明','2024/10/29','A'),(N'小明','2024/10/30','A'),(N'小明','2024/10/31','A');

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM

Demo:SQL 2016

『修正版』
```
CREATE TABLE da (
Name nvarchar(20),
SetDate date,
Code nvarchar(5));

INSERT INTO da (Name, SetDate,Code) VALUES
(N'大白','2024/09/1','A'),(N'大白','2024/09/2','A'),(N'大白','2024/09/3','A'),(N'大白','2024/09/4','A')
,(N'大白','2024/09/5',N'休'),(N'大白','2024/09/6',N'休'),(N'大白','2024/09/7','A'),(N'大白','2024/09/8','A')
,(N'大白','2024/09/9','A'),(N'大白','2024/09/10',N'休'),(N'大白','2024/09/11','A'),(N'大白','2024/09/12',N'休')
,(N'大白','2024/09/13',N'休'),(N'大白','2024/09/14','B'),(N'大白','2024/09/15','B'),(N'大白','2024/09/16','B')
,(N'大白','2024/09/17','B'),(N'大白','2024/09/18','B'),(N'大白','2024/09/19',N'休'),(N'大白','2024/09/20',N'休')
,(N'大白','2024/09/21','A'),(N'大白','2024/09/22','A'),(N'大白','2024/09/23','A'),(N'大白','2024/09/24','A')
,(N'大白','2024/09/25','A'),(N'大白','2024/09/26',N'休'),(N'大白','2024/09/27',N'休'),(N'大白','2024/09/28','A')
,(N'大白','2024/09/29','A'),(N'大白','2024/09/30','A')
,(N'大白','2024/10/1',N'特'),(N'大白','2024/10/2',N'特'),(N'大白','2024/10/3','B'),(N'大白','2024/10/4','B')
,(N'大白','2024/10/5',N'休'),(N'大白','2024/10/6',N'休'),(N'大白','2024/10/7','B'),(N'大白','2024/10/8','B')
,(N'大白','2024/10/9','B'),(N'大白','2024/10/10',N'休'),(N'大白','2024/10/11','B'),(N'大白','2024/10/12',N'休')
,(N'大白','2024/10/13',N'休'),(N'大白','2024/10/14','A'),(N'大白','2024/10/15','A'),(N'大白','2024/10/16','A')
,(N'大白','2024/10/17','A'),(N'大白','2024/10/18','A'),(N'大白','2024/10/19',N'休'),(N'大白','2024/10/20',N'休')
,(N'大白','2024/10/21','B'),(N'大白','2024/10/22','B'),(N'大白','2024/10/23','B'),(N'大白','2024/10/24','B')
,(N'大白','2024/10/25','B'),(N'大白','2024/10/26',N'休'),(N'大白','2024/10/27',N'休'),(N'大白','2024/10/28','B')
,(N'大白','2024/10/29','B'),(N'大白','2024/10/30','B'),(N'大白','2024/10/31','B')
,(N'小明','2024/10/1','A'),(N'小明','2024/10/2','A'),(N'小明','2024/10/3','A'),(N'小明','2024/10/4','A')
,(N'小明','2024/10/5',N'休'),(N'小明','2024/10/6',N'休'),(N'小明','2024/10/7','A'),(N'小明','2024/10/8','A')
,(N'小明','2024/10/9','A'),(N'小明','2024/10/10',N'休'),(N'小明','2024/10/11','A'),(N'小明','2024/10/12',N'休')
,(N'小明','2024/10/13',N'休'),(N'小明','2024/10/14','B'),(N'小明','2024/10/15','B'),(N'小明','2024/10/16','B')
,(N'小明','2024/10/17','B'),(N'小明','2024/10/18','B'),(N'小明','2024/10/19',N'休'),(N'小明','2024/10/20',N'休')
,(N'小明','2024/10/21','A'),(N'小明','2024/10/22','A'),(N'小明','2024/10/23','A'),(N'小明','2024/10/24','A')
,(N'小明','2024/10/25','A'),(N'小明','2024/10/26',N'休'),(N'小明','2024/10/27',N'休'),(N'小明','2024/10/28','A')
,(N'小明','2024/10/29','A'),(N'小明','2024/10/30','A'),(N'小明','2024/10/31','A');  
```
```
-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM
```
[Demo:SQL 2016](https://dbfiddle.uk/-Q2U3dyj)

修改

純真的人 iT邦大師 1 級 ‧ 2024-10-16 08:56:06 檢舉

那句SQL要用在跨月列出的話
我知道怎樣改~就加上跨月條件

Row_Number() OVER (PARTITION BY Name,format(SetDate,'yyyy-MM') ORDER BY SetDate) AS id

--在此join條件加上跨月
LEFT JOIN (
   略......
)  AS K on format(a.SetDate,'yyyy-MM') = format(k.SetDate,'yyyy-MM')

你的跨月寫法也是滿有趣的~

Left(SetDate,7)

然後~列出跑秒數過久的SQL好了~
昨天講錯了~是當月排班列出

跑21秒的SQL

declare @StartDate date = '2024/10/1'
,@DNO varchar(20) = 'xxx'

declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

declare @Shift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)

insert into @Shift
略.....(當月排班)

;WITH
NewShift as (
	select a.GroupName
	,a.PNo
	,a.PName
	,a.SetDate
	,isNull((
		CASE WHEN a.SetDate > K1.SetDate THEN k1.Code ELSE (case when a.Code in(N'特',N'休') then null else a.Code end) END
	),(
		CASE WHEN a.SetDate < K2.SetDate THEN k2.Code ELSE a.Code END
	)) Code
	from @Shift a
	left join (
		select *
		from (
			SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate ) AS RN
			,*
			FROM @Shift b
			WHERE b.Code not in(N'特',N'休')
		) k
		where RN = 1
	) k1 on a.PNo = k1.PNo
	left join (
		select *
		from (
			SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate desc) AS RN
			,*
			FROM @Shift b
			WHERE b.Code not in(N'特',N'休')
		) k
		where RN = 1
	) k2 on a.PNo = k2.PNo
)
,CTE01 AS (
	select GroupName
	,PNo
	,PName
	,M.SetDate
	,M.Code
	,1 + SUM(M.Num) OVER (PARTITION BY M.PNo ORDER BY M.SetDate) AS No
	FROM (
		SELECT a.*,
			CASE WHEN Code = LAG(Code,1,Code) OVER (PARTITION BY PNo ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM NewShift a
	) M
)
,CTE02 AS (
	select GroupName
	,PNo
	,PName
	,Code
	,No
	,Min(SetDate) AS MinDate
	,Max(SetDate) AS MaxDate
	FROM CTE01
	GROUP BY GroupName
	,PNo
	,PName
	,Code
	,No
)
,CTE03 AS (
	select GroupName
	,PNo
	,PName
	,No
	,Code
	,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE02
)

select GroupName
,PNo
,PName
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.PNo = b.PNo
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

跑1秒的SQL

declare @StartDate date = '2024/10/1'
,@DNO varchar(20) = 'xxx'

declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

declare @Shift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)

insert into @Shift
略.....(當月排班)

declare @NewShift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)
insert into @NewShift
select a.GroupName
,a.PNo
,a.PName
,a.SetDate
,isNull((
	CASE WHEN a.SetDate > K1.SetDate THEN k1.Code ELSE (case when a.Code in(N'特',N'休') then null else a.Code end) END
),(
	CASE WHEN a.SetDate < K2.SetDate THEN k2.Code ELSE a.Code END
)) Code
from @Shift a
left join (
	select *
	from (
		SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate ) AS RN
		,*
		FROM @Shift b
		WHERE b.Code not in(N'特',N'休')
	) k
	where RN = 1
) k1 on a.PNo = k1.PNo
left join (
	select *
	from (
		SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate desc) AS RN
		,*
		FROM @Shift b
		WHERE b.Code not in(N'特',N'休')
	) k
	where RN = 1
) k2 on a.PNo = k2.PNo

;WITH
CTE01 AS (
	select GroupName
	,PNo
	,PName
	,M.SetDate
	,M.Code
	,1 + SUM(M.Num) OVER (PARTITION BY M.PNo ORDER BY M.SetDate) AS No
	FROM (
		SELECT a.*,
			CASE WHEN Code = LAG(Code,1,Code) OVER (PARTITION BY PNo ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM @NewShift a
	) M
)
,CTE02 AS (
	select GroupName
	,PNo
	,PName
	,Code
	,No
	,Min(SetDate) AS MinDate
	,Max(SetDate) AS MaxDate
	FROM CTE01
	GROUP BY GroupName
	,PNo
	,PName
	,Code
	,No
)
,CTE03 AS (
	select GroupName
	,PNo
	,PName
	,No
	,Code
	,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE02
)

select GroupName
,PNo
,PName
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.PNo = b.PNo
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

你可以看看問題在哪裡，我只是把 NewShift 表，移到 WITH 外面，就變快了@@...

那句SQL要用在跨月列出的話
我知道怎樣改~就加上跨月條件
```
Row_Number() OVER (PARTITION BY Name,format(SetDate,'yyyy-MM') ORDER BY SetDate) AS id

--在此join條件加上跨月
LEFT JOIN (
   略......
)  AS K on format(a.SetDate,'yyyy-MM') = format(k.SetDate,'yyyy-MM')
```

你的跨月寫法也是滿有趣的~
```
Left(SetDate,7)
```

然後~列出跑秒數過久的SQL好了~
昨天講錯了~是當月排班列出

跑21秒的SQL
```
declare @StartDate date = '2024/10/1'
,@DNO varchar(20) = 'xxx'

declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

declare @Shift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)

insert into @Shift
略.....(當月排班)

;WITH
NewShift as (
	select a.GroupName
	,a.PNo
	,a.PName
	,a.SetDate
	,isNull((
		CASE WHEN a.SetDate > K1.SetDate THEN k1.Code ELSE (case when a.Code in(N'特',N'休') then null else a.Code end) END
	),(
		CASE WHEN a.SetDate < K2.SetDate THEN k2.Code ELSE a.Code END
	)) Code
	from @Shift a
	left join (
		select *
		from (
			SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate ) AS RN
			,*
			FROM @Shift b
			WHERE b.Code not in(N'特',N'休')
		) k
		where RN = 1
	) k1 on a.PNo = k1.PNo
	left join (
		select *
		from (
			SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate desc) AS RN
			,*
			FROM @Shift b
			WHERE b.Code not in(N'特',N'休')
		) k
		where RN = 1
	) k2 on a.PNo = k2.PNo
)
,CTE01 AS (
	select GroupName
	,PNo
	,PName
	,M.SetDate
	,M.Code
	,1 + SUM(M.Num) OVER (PARTITION BY M.PNo ORDER BY M.SetDate) AS No
	FROM (
		SELECT a.*,
			CASE WHEN Code = LAG(Code,1,Code) OVER (PARTITION BY PNo ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM NewShift a
	) M
)
,CTE02 AS (
	select GroupName
	,PNo
	,PName
	,Code
	,No
	,Min(SetDate) AS MinDate
	,Max(SetDate) AS MaxDate
	FROM CTE01
	GROUP BY GroupName
	,PNo
	,PName
	,Code
	,No
)
,CTE03 AS (
	select GroupName
	,PNo
	,PName
	,No
	,Code
	,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE02
)

select GroupName
,PNo
,PName
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.PNo = b.PNo
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

```
![https://ithelp.ithome.com.tw/upload/images/20241016/20061369mMFKjoQLtW.png](https://ithelp.ithome.com.tw/upload/images/20241016/20061369mMFKjoQLtW.png)

跑1秒的SQL
```
declare @StartDate date = '2024/10/1'
,@DNO varchar(20) = 'xxx'

declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

declare @Shift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)

insert into @Shift
略.....(當月排班)

declare @NewShift table(
	GroupName nvarchar(50)
	,PNo nvarchar(50)
	,PName nvarchar(50)
	,SetDate date
	,Code nvarchar(10)
)
insert into @NewShift
select a.GroupName
,a.PNo
,a.PName
,a.SetDate
,isNull((
	CASE WHEN a.SetDate > K1.SetDate THEN k1.Code ELSE (case when a.Code in(N'特',N'休') then null else a.Code end) END
),(
	CASE WHEN a.SetDate < K2.SetDate THEN k2.Code ELSE a.Code END
)) Code
from @Shift a
left join (
	select *
	from (
		SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate ) AS RN
		,*
		FROM @Shift b
		WHERE b.Code not in(N'特',N'休')
	) k
	where RN = 1
) k1 on a.PNo = k1.PNo
left join (
	select *
	from (
		SELECT Row_Number() OVER (PARTITION BY PNO ORDER BY b.SetDate desc) AS RN
		,*
		FROM @Shift b
		WHERE b.Code not in(N'特',N'休')
	) k
	where RN = 1
) k2 on a.PNo = k2.PNo

;WITH
CTE01 AS (
	select GroupName
	,PNo
	,PName
	,M.SetDate
	,M.Code
	,1 + SUM(M.Num) OVER (PARTITION BY M.PNo ORDER BY M.SetDate) AS No
	FROM (
		SELECT a.*,
			CASE WHEN Code = LAG(Code,1,Code) OVER (PARTITION BY PNo ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM @NewShift a
	) M
)
,CTE02 AS (
	select GroupName
	,PNo
	,PName
	,Code
	,No
	,Min(SetDate) AS MinDate
	,Max(SetDate) AS MaxDate
	FROM CTE01
	GROUP BY GroupName
	,PNo
	,PName
	,Code
	,No
)
,CTE03 AS (
	select GroupName
	,PNo
	,PName
	,No
	,Code
	,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE02
)

select GroupName
,PNo
,PName
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.PNo = b.PNo
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

```
![https://ithelp.ithome.com.tw/upload/images/20241016/20061369qHPUxauRbg.png](https://ithelp.ithome.com.tw/upload/images/20241016/20061369qHPUxauRbg.png)

你可以看看問題在哪裡，我只是把 NewShift 表，移到 WITH 外面，就變快了@@...

修改

rogeryao iT邦超人 7 級 ‧ 2024-10-16 09:25:15 檢舉

,CTE01 AS (

其實你只要測這一行以上的速度就可以了，以下的程式碼是一樣的
若是差距很大的話，我只能猜測是 SQL Sever 配置記憶體的方式不一樣，
才導致計算速度的落差

純真的人 iT邦大師 1 級 ‧ 2024-10-16 09:43:17 檢舉

結果我~SQL一段一段的慢慢拆開測試是哪邊有問題...
結果是出在最後面@@...

;WITH
NewShift as (
略...
)
,CTE01 AS (
略...
)
,CTE02 AS (
略...
)
,CTE03 AS (
略...
)

--27位員工 * 31天 = 837筆 跑0.5秒
select GroupName
,PNo
,PName
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

--27位員工 * 31天 = 837筆 跑21秒
select GroupName
,PNo
,PName
,stuff((
	select ',' + PartStr
	from CTE03 b
	where a.PNo = b.PNo
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

純真的人 iT邦大師 1 級 ‧ 2024-10-16 09:47:42 檢舉

把那段子查詢註解後~速度就正常了0.0...

select GroupName
,PNo
,PName
--,stuff((
--	select ',' + PartStr
--	from CTE03 b
--	where a.PNo = b.PNo
--	order by no
--	for xml path('')
--),1,1,'') as AllStr
FROM CTE03 a
GROUP BY GroupName
,PNo
,PName

純真的人 iT邦大師 1 級 ‧ 2024-10-16 10:49:54 檢舉

看起來~只有升級2017版後~
這個函數才能解決效率變差的問題吧@@

STRING_AGG()

rogeryao iT邦超人 7 級 ‧ 2024-10-16 11:34:39 檢舉

你有用我的修正版跟你的最後一版
去比對資料正確性跟速度嗎？

因為我一直覺得 WITH 這一段 SQL 的邏輯怪怪的
;WITH
NewShift as

純真的人 iT邦大師 1 級 ‧ 2024-10-16 13:55:49 檢舉

我直接套你的SQL
2筆很快~
可是筆數一多~好像就跑不完...@@

declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxxx'

declare @da table(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO @da (Name, SetDate,Code)
略....(實際當月班別)

SELECT *
FROM @da;

-- 每月 1 日'休'、'特', 找到第一個班別向上補
WITH 
CTE01 AS (
	SELECT a.Name,a.SetDate,
	CASE WHEN a.SetDate < K.SetDate THEN K.Code ELSE a.Code END AS Code
	FROM @da a
	LEFT JOIN (
		SELECT * FROM (
		SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS RN,*
		FROM @da
		WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
		WHERE RN =1  
	) AS K ON K.Name=a.Name
)

-- 向下補班別  
,CTE02 AS (
	SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS id,
	Name,SetDate,
	CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
	FROM CTE01
)
,CTE03 AS (
	SELECT step_l.Name,step_l.SetDate,step_2.CodeX as Code
	FROM ( 
		SELECT id,Name,SetDate,CodeX, 
		SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name ORDER BY SetDate) as rank_id 
		FROM CTE02
	) as step_l 
	LEFT JOIN ( 
		SELECT id,Name,SetDate,CodeX, 
		Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS join_id 
		FROM CTE02 WHERE CodeX IS NOT NULL
	) as step_2 
	ON step_l.Name = step_2.Name 
	AND step_l.rank_id = step_2.join_id
)

-- Code 內無'休'、'特'
,CTE04 AS (
	SELECT M.Name,M.SetDate,M.Code,1 + SUM(M.Num) OVER (PARTITION BY M.Name ORDER BY M.SetDate) AS No
	FROM (
		SELECT CTE03.*,
		CASE WHEN Code = LAG(Code,1,Code) OVER (
		PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM CTE03
	) M
)
,CTE05 AS (
	SELECT Name,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
	FROM CTE04
	GROUP BY Name,Code,No
)
,CTE06 AS (
	SELECT Name,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE05
)

SELECT Name
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name
	order by no
	for xml path('')
),1,1,'') as AllStr
--,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06 a
GROUP BY Name

跑了13分鐘...我直接按中止查詢@@...

我直接套你的SQL
2筆很快~
可是筆數一多~好像就跑不完...@@

```
declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxxx'

declare @da table(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO @da (Name, SetDate,Code)
略....(實際當月班別)

SELECT *
FROM @da;

-- 每月 1 日'休'、'特', 找到第一個班別向上補
WITH 
CTE01 AS (
	SELECT a.Name,a.SetDate,
	CASE WHEN a.SetDate < K.SetDate THEN K.Code ELSE a.Code END AS Code
	FROM @da a
	LEFT JOIN (
		SELECT * FROM (
		SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS RN,*
		FROM @da
		WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
		WHERE RN =1  
	) AS K ON K.Name=a.Name
)

-- 向下補班別  
,CTE02 AS (
	SELECT Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS id,
	Name,SetDate,
	CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
	FROM CTE01
)
,CTE03 AS (
	SELECT step_l.Name,step_l.SetDate,step_2.CodeX as Code
	FROM ( 
		SELECT id,Name,SetDate,CodeX, 
		SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name ORDER BY SetDate) as rank_id 
		FROM CTE02
	) as step_l 
	LEFT JOIN ( 
		SELECT id,Name,SetDate,CodeX, 
		Row_Number() OVER (PARTITION BY Name ORDER BY SetDate) AS join_id 
		FROM CTE02 WHERE CodeX IS NOT NULL
	) as step_2 
	ON step_l.Name = step_2.Name 
	AND step_l.rank_id = step_2.join_id
)

-- Code 內無'休'、'特'
,CTE04 AS (
	SELECT M.Name,M.SetDate,M.Code,1 + SUM(M.Num) OVER (PARTITION BY M.Name ORDER BY M.SetDate) AS No
	FROM (
		SELECT CTE03.*,
		CASE WHEN Code = LAG(Code,1,Code) OVER (
		PARTITION BY Name ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
		FROM CTE03
	) M
)
,CTE05 AS (
	SELECT Name,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
	FROM CTE04
	GROUP BY Name,Code,No
)
,CTE06 AS (
	SELECT Name,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
	FROM CTE05
)

SELECT Name
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name
	order by no
	for xml path('')
),1,1,'') as AllStr
--,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06 a
GROUP BY Name
```

![https://ithelp.ithome.com.tw/upload/images/20241016/20061369aPH7ClOGbF.png](https://ithelp.ithome.com.tw/upload/images/20241016/20061369aPH7ClOGbF.png)

跑了13分鐘...我直接按中止查詢@@...

修改

rogeryao iT邦超人 7 級 ‧ 2024-10-16 14:00:27 檢舉

這內容不是我最後一版的修正版（2024-10-16 08:39:09）
修正版內有 YM 這個欄位

純真的人 iT邦大師 1 級 ‧ 2024-10-16 14:05:56 檢舉

後來我改成實際資料表儲存~速度就查到了@@a

好像是因為 declare 就宣告會影響WITH效能存取..

我在試試（2024-10-16 08:39:09）若用 declare 是不是可以@@...

純真的人 iT邦大師 1 級 ‧ 2024-10-16 14:18:39 檢舉

果然是 declare 宣告表格問題@@..
但是處理查詢又不能真的存表格..(因為那是很多join表格來的)

declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxxx'

declare @da table(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO @da (Name, SetDate,Code)
略............(實際班別資料)

SELECT *
FROM @da;

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM @da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM

跑太久~按中止

果然是 declare 宣告表格問題@@..
但是處理查詢又不能真的存表格..(因為那是很多join表格來的)

```
declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxxx'

declare @da table(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO @da (Name, SetDate,Code)
略............(實際班別資料)

SELECT *
FROM @da;

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM @da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM

```

![https://ithelp.ithome.com.tw/upload/images/20241016/20061369JBV8P65NtK.png](https://ithelp.ithome.com.tw/upload/images/20241016/20061369JBV8P65NtK.png)

跑太久~按中止

修改

rogeryao iT邦超人 7 級 ‧ 2024-10-16 14:21:59 檢舉

我的解法不需要計算當月最後一天

純真的人 iT邦大師 1 級 ‧ 2024-10-16 14:25:08 檢舉

恩~我在想想~如果存實際表格的話~
他們這個月有改班表才刷新~實際表格資料~
其他報表查詢就直接抓已紀錄的實際表格資料

純真的人 iT邦大師 1 級 ‧ 2024-10-16 14:51:29 檢舉

剛剛~想到如果把 declare 改成宣告暫存表格 #da
查詢速度就ok了@@~

declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxx'

create table #da(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO #da (Name, SetDate,Code)
略.......

SELECT *
FROM #da;

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM #da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM

DROP TABLE #da

剛剛~想到如果把 declare 改成宣告 暫存表格 #da
查詢速度就ok了@@~

```
declare @StartDate date = '2024/8/1'
,@DNO varchar(20) = 'xxx'

create table #da(
Name nvarchar(20),
SetDate date,
Code nvarchar(5));
declare @EndDate date = dateadd(day,-1,dateadd(month,1,@StartDate))

INSERT INTO #da (Name, SetDate,Code)
略.......

SELECT *
FROM #da;

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM #da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('2A','2C','3A','3B','3C')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('2A','2C','3A','3B','3C') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05)
/*
SELECT Name,YM,STRING_AGG(PartStr,',') WITHIN GROUP (ORDER BY No) AS AllStr
FROM CTE06
GROUP BY Name,YM  
*/
SELECT Name,YM
,stuff((
	select ',' + PartStr
	from CTE06 b
	where a.Name = b.Name and a.YM = b.YM
	order by no
	for xml path('')
),1,1,'') as AllStr
FROM CTE06 a
GROUP BY Name,YM

DROP TABLE #da

```

修改

rogeryao iT邦超人 7 級 ‧ 2024-10-16 14:57:34 檢舉

有用我的修正版跟你的最後一版
去比對資料正確性跟速度嗎？

純真的人 iT邦大師 1 級 ‧ 2024-10-16 14:58:26 檢舉

這三種表格用法~在微軟解釋記憶體部分好像我看不出差異..

create table da
create table #da
declare @da table

https://learn.microsoft.com/zh-tw/sql/relational-databases/in-memory-oltp/faster-temp-table-and-table-variable-by-using-memory-optimization?view=sql-server-ver16

純真的人 iT邦大師 1 級 ‧ 2024-10-16 15:03:24 檢舉

速度你比較快~
資料正確性你的對~
從到職日開始上班的日期也正確~

rogeryao iT邦超人 7 級 ‧ 2024-10-16 15:19:16 檢舉

恭喜，打完收工

純真的人 iT邦大師 1 級 ‧ 2024-10-16 15:20:26 檢舉

貼到正式空間的資料庫查詢也沒問題~謝謝你!

rogeryao iT邦超人 7 級 ‧ 2024-10-17 21:20:14 檢舉

案例一：遞迴查詢取代 xml path 組合字串

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05),
-- 遞迴查詢組合字串
CTE07 AS (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY No) AS PX
FROM CTE06),  
CTE08 AS (
SELECT Name,YM,No,PX,
CAST(PartStr as nvarchar(200)) as AllStr,1 as ID
FROM CTE07
UNION ALL
SELECT NS.Name,NS.YM,NS.No,NS.PX,
CAST(CTE08.AllStr +','+ NS.PartStr as nvarchar(200)) as AllStr,
ID + 1 AS ID
FROM CTE07 AS NS
INNER JOIN CTE08 ON NS.Name = CTE08.Name
AND NS.YM = CTE08.YM
AND NS.PX - 1 = CTE08.PX
)
--
SELECT A.Name,A.YM,A.AllStr
FROM CTE08 AS A
INNER JOIN (  
SELECT Name,YM,MAX(ID) AS MAXID
FROM CTE08
GROUP BY Name,YM) AS B ON B.Name = A.Name 
AND B.YM = A.YM
AND B.MAXID = A.ID
ORDER BY Name,YM

Demo:SQL 2016

遞迴查詢組合字串:測試資料

案例二：遞迴查詢取代 xml path 組合字串

-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05),
-- 遞迴查詢組合字串
CTE07 AS (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY No) AS PX
FROM CTE06),  
CTE08 AS (
SELECT Name,YM,No,PX,
CAST(PartStr as nvarchar(200)) as AllStr,1 as ID
FROM CTE07
UNION ALL
SELECT NS.Name,NS.YM,NS.No,NS.PX,
CAST(CTE08.AllStr +','+ NS.PartStr as nvarchar(200)) as AllStr,
ID + 1 AS ID
FROM CTE07 AS NS
INNER JOIN CTE08 ON NS.Name = CTE08.Name
AND NS.YM = CTE08.YM
AND NS.PX - 1 = CTE08.PX
)
--
SELECT Name,YM,AllStr
FROM (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY ID Desc) AS Pos
FROM CTE08
) T
WHERE Pos = 1 
ORDER BY Name,YM

Demo:SQL 2016

案例一：遞迴查詢取代 xml path 組合字串
```
-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05),
-- 遞迴查詢組合字串
CTE07 AS (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY No) AS PX
FROM CTE06),  
CTE08 AS (
SELECT Name,YM,No,PX,
CAST(PartStr as nvarchar(200)) as AllStr,1 as ID
FROM CTE07
UNION ALL
SELECT NS.Name,NS.YM,NS.No,NS.PX,
CAST(CTE08.AllStr +','+ NS.PartStr as nvarchar(200)) as AllStr,
ID + 1 AS ID
FROM CTE07 AS NS
INNER JOIN CTE08 ON NS.Name = CTE08.Name
AND NS.YM = CTE08.YM
AND NS.PX - 1 = CTE08.PX
)
--
SELECT A.Name,A.YM,A.AllStr
FROM CTE08 AS A
INNER JOIN (  
SELECT Name,YM,MAX(ID) AS MAXID
FROM CTE08
GROUP BY Name,YM) AS B ON B.Name = A.Name 
AND B.YM = A.YM
AND B.MAXID = A.ID
ORDER BY Name,YM
```
[Demo:SQL 2016](https://dbfiddle.uk/NXwOGUBa)

[ 遞迴查詢組合字串:測試資料](https://dbfiddle.uk/QvG3dXxp)

案例二：遞迴查詢取代 xml path 組合字串
```
-- 分割年月
WITH CTE00 AS (
SELECT Name,LEFT(SetDate,7) AS 'YM',SetDate,Code
FROM da),  
-- 每月 1 日'休'、'特', 找到第一個班別向上補
CTE01 AS (
SELECT CTE00.Name,CTE00.YM,CTE00.SetDate,
CASE WHEN CTE00.SetDate < K.SetDate THEN K.Code ELSE CTE00.Code END AS Code
FROM CTE00
LEFT JOIN (
SELECT * FROM (
SELECT Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS RN,*
FROM CTE00
WHERE Code IN ('A','B')) AS K
WHERE RN =1  
) AS K ON K.Name=CTE00.Name AND K.YM=CTE00.YM),
-- 向下補班別  
CTE02 AS (
SELECT Name,SetDate,YM,
CASE WHEN Code NOT IN ('A','B') THEN NULL ELSE Code END AS CodeX
FROM CTE01),
--
CTE03 AS (
SELECT step_l.Name,step_l.YM,step_l.SetDate,step_2.CodeX as Code
FROM ( 
SELECT Name,YM,SetDate,CodeX, 
SUM(CASE WHEN CodeX IS NULL THEN 0 ELSE 1 END) OVER (PARTITION BY Name,YM ORDER BY SetDate) as rank_id 
FROM CTE02) as step_l 
LEFT JOIN ( 
SELECT Name,YM,SetDate,CodeX, 
Row_Number() OVER (PARTITION BY Name,YM ORDER BY SetDate) AS join_id 
FROM CTE02 WHERE CodeX IS NOT NULL) as step_2 
ON step_l.Name = step_2.Name 
AND step_l.YM = step_2.YM
AND step_l.rank_id = step_2.join_id),
-- Code 內無'休'、'特'
CTE04 AS (
SELECT M.Name,M.YM,M.SetDate,M.Code,1 + SUM(M.Num) OVER (
PARTITION BY M.Name,M.YM ORDER BY M.SetDate) AS No
FROM (
SELECT CTE03.*,
CASE WHEN Code = LAG(Code,1,Code) OVER (
PARTITION BY Name,YM ORDER BY SetDate) THEN 0 ELSE 1 END AS Num
FROM CTE03) M),  
CTE05 AS (
SELECT Name,YM,Code,No,Min(SetDate) AS MinDate,Max(SetDate) AS MaxDate
FROM CTE04
GROUP BY Name,YM,Code,No),
CTE06 AS (
SELECT Name,YM,No,Code,Code+':'+Right(MinDate,2)+'~'+Right(MaxDate,2) AS PartStr
FROM CTE05),
-- 遞迴查詢組合字串
CTE07 AS (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY No) AS PX
FROM CTE06),  
CTE08 AS (
SELECT Name,YM,No,PX,
CAST(PartStr as nvarchar(200)) as AllStr,1 as ID
FROM CTE07
UNION ALL
SELECT NS.Name,NS.YM,NS.No,NS.PX,
CAST(CTE08.AllStr +','+ NS.PartStr as nvarchar(200)) as AllStr,
ID + 1 AS ID
FROM CTE07 AS NS
INNER JOIN CTE08 ON NS.Name = CTE08.Name
AND NS.YM = CTE08.YM
AND NS.PX - 1 = CTE08.PX
)
--
SELECT Name,YM,AllStr
FROM (
SELECT *,ROW_NUMBER() OVER (PARTITION BY Name,YM ORDER BY ID Desc) AS Pos
FROM CTE08
) T
WHERE Pos = 1 
ORDER BY Name,YM
```
[Demo:SQL 2016](https://dbfiddle.uk/qLkyDu19)

修改

rogeryao iT邦超人 7 級 ‧ 2024-10-17 21:30:11 檢舉

可否幫忙用大量數據測一下最後一版（使用 xml path 組合字串）
與案例一、案例二遞迴查詢組合字串時間相差多少，謝謝。

純真的人 iT邦大師 1 級 ‧ 2024-10-18 08:35:03 檢舉

兩個都查詢過久取消~

單純2筆的資料~馬上出來~

rogeryao iT邦超人 7 級 ‧ 2024-10-18 10:44:30 檢舉

為取得時間相差多少，我在 Win 11 上的 SQL 2019 建立 1380 筆資料
1.STRING_AGG : 0.084 秒
2.xml path : 2.435 秒
3.遞迴查詢組合字串用 ROW_NUMBER 取得指定筆資料 : 14.874 秒
4.遞迴查詢組合字串 INNER JOIN + MAX 取得指定筆資料 : 30.976 秒

結論 :
1.指令優先選擇 : STRING_AGG > xml path > 遞迴查詢組合字串
2.取得指定筆資料 : ROW_NUMBER > INNER JOIN + MAX