select amount from test as A -- left join group as B on B.person_id=A.person_id...
in 配 bind param 的寫法: // in的資料 $person_no = implode(',',$dataArray); // 產生bind要用...
select contest_id, hacker_id, name , ifnull(sum(tsub),0) as total_submissio...
php抓到的是html的name,不是id 您新增的東西應該會在 $_POST['terms'] 中 還有就是您的jQuery段落的這個寫法name不確定是否會...