DAY 16
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## Day16 - Codewars 刷題

``````Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on.

For example, Penny drinks the third can of cola and the queue will look like this:

Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny
Write a program that will return the name of the person who will drink the n-th cola.

Input
The input data consist of an array which contains at least 1 name, and single integer n which may go as high as the biggest number your language of choice supports (if there's such limit, of course).

Output / Examples
Return the single line — the name of the person who drinks the n-th can of cola. The cans are numbered starting from 1.

whoIsNext(["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"], 1) == "Sheldon"
whoIsNext(["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"], 52) == "Penny"
whoIsNext(["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"], 7230702951) == "Leonard"
``````
``````def who_is_next(names, r)
end

names = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]

Test.assert_equals(who_is_next(names, 1), "Sheldon")
Test.assert_equals(who_is_next(names, 52), "Penny")
Test.assert_equals(who_is_next(names, 7230702951), "Leonard")
``````
``````A square of squares
You like building blocks. You especially like building blocks that are squares. And what you even like more, is to arrange them into a square of square building blocks!

However, sometimes, you can't arrange them into a square. Instead, you end up with an ordinary rectangle! Those blasted things! If you just had a way to know, whether you're currently working in vain… Wait! That's it! You just have to check if your number of building blocks is a perfect square.
``````
``````def is_square(x)
false
end

describe "is_square" do
it "should work for some examples" do
Test.assert_equals (is_square (-1)), false, "-1 is not a perfect square"
Test.assert_equals (is_square  0),   true,  "0 is a perfect square (0 * 0)"
Test.assert_equals (is_square  3),   false,  "3 is not a perfect square"
Test.assert_equals (is_square  4),    true,   "4 is a perfect square (2 * 2)"
Test.assert_equals (is_square 25),    true,  "25 is a perfect square (5 * 5)"
Test.assert_equals (is_square 26),   false, "26 is not a perfect square"
end
end
``````

``````# Double Cola
def who_is_next(names, r)
len = names.length
while r > len
r -= len
len *= 2
end
names[(r-1)/(len/names.length)]
end

# You're a square!
def is_square(x)
x < 0 ? false : Math.sqrt(x) % 1 == 0
end
``````