1295. Find Numbers with Even Number of Digits

Given an array nums of integers, return how many of them contain an even number of digits.

• Example 1:
  Input: nums = [12,345,2,6,7896]
  Output: 2
  Explanation:
  12 contains 2 digits (even number of digits).
  345 contains 3 digits (odd number of digits).
  2 contains 1 digit (odd number of digits).
  6 contains 1 digit (odd number of digits).
  7896 contains 4 digits (even number of digits).
  Therefore only 12 and 7896 contain an even number of digits.

• Example 2:
  Input: nums = [555,901,482,1771]
  Output: 1
  Explanation:
  Only 1771 contains an even number of digits.

var findNumbers = function(nums) {
  let count = 0;  
  nums.forEach((i, idx) => {
    if(i.length % 2 == 0)
        count += Array.from(new Set(String(i).split(''))).length % 2 == 0 ? 1 : 0;
  });
  return count;
};