小弟想到兩種方式
如果在高手眼中太拙劣請見諒

import random

options = ['apple', 'pear', 'peach', 'orange', 'peach']

def ver1(n):
    for i in range(n):
        a = random.sample(options,3)
        if a.count('peach') > 1:
            continue
        else:
            print(a)


def ver2(n):
    for i in range(n):
        set_obj = set(options)
        b = random.sample(set_obj, 3)
        print(b)

ver1是以count()過濾掉出現兩次的情況。
ver2則是以set()內元素不會重複的特性，過濾掉原本list的重複元素。

options = ['apple', 'pear', 'peach', 'orange', 'lemon', 'peach']
random.shuffle(options)
print(options[:3])

或

random.sample ( ['apple', 'pear', 'peach', 'orange', 'lemon', 'peach'], k=3)

import random
fruit = ['apple', 'pear', 'peach', 'orange', 'peach']

print(random.sample(set(fruit),3))