(Flask,python) OSError: [Errno 50] Protocol not available

python flask pyscript html python3

jton 2023-01-18 14:30:54 ‧ 692 瀏覽

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Q: 如何結合html和python flask
我的目標是使現有網站能(用flask)在網址取值

html 代碼

<script type=module src=main_joy_01_12.js></script><my-header></my-header>

<head>
    <link rel="stylesheet" href="https://pyscript.net/latest/pyscript.css" />
    <script defer src="https://pyscript.net/latest/pyscript.js"></script>
</head>

<html>
    <p>fix title/contaxt</p>
    <h1>this is the data extract from mysql: Nordic85678</h1>
    </body>
</html>



<py-config>
    packages = ["flask"]
</py-config>

<py-script>

    # pyscript 這裡能在 html 使用python
    # 以下為普通的 python 代碼, 單獨跑python腳本沒問題
    from flask import Flask, request
    
    # create the Flask app
    app = Flask(__name__)
    
    
    @app.route('/data')
    def query_example():
        # if key doesn't exist, returns None
        P_ID = request.args.get('P_ID')
    
        # if key doesn't exist, returns None
        P_TITLE = request.args.get('P_TITLE')
    
        return ''' 
    
                <script type=module src=main_joy_01_12.js></script><my-header></my-header>
    
    <head>
        <link rel="stylesheet" href="https://pyscript.net/latest/pyscript.css" />
        <script defer src="https://pyscript.net/latest/pyscript.js"></script>
    </head>
    
    <html>
        <p>fix title/contaxt</p>
        <h1>this is the data extract from mysql: {}</h1>
    
        </body>
    </html>
    
    
    '''.format( P_TITLE)
    
                
    if __name__ == '__main__':
        # run app in debug mode on port 5000
        app.run(debug=True, port=5000)
    
</py-script>

<my-footer></my-footer>

報錯

Traceback (most recent call last):
  File "/lib/python3.10/site-packages/_pyodide/_base.py", line 435, in eval_code
    .run(globals, locals)
  File "/lib/python3.10/site-packages/_pyodide/_base.py", line 304, in run
    coroutine = eval(self.code, globals, locals)
  File "<exec>", line 235, in <module>
  File "/lib/python3.10/site-packages/flask/app.py", line 1188, in run
    run_simple(t.cast(str, host), port, self, **options)
  File "/lib/python3.10/site-packages/werkzeug/serving.py", line 1062, in run_simple
    s = prepare_socket(hostname, port)
  File "/lib/python3.10/site-packages/werkzeug/serving.py", line 898, in prepare_socket
    s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
OSError: [Errno 50] Protocol not available

網頁呈現

要如何修復報錯，感謝

我的想法是可以輸入諸如 https://www.happy.com/data?P-ID=en_1-01 之類的內容

然後顯示輸入數據“您是在查找 en_1-01 嗎?” 在現有網站上？
類似這樣的效果

看更多先前的討論...收起先前的討論...

froce iT邦大師 1 級 ‧ 2023-01-18 14:38:08 檢舉

Browser不可能有能力開port，別傻了

jton iT邦新手 5 級 ‧ 2023-01-18 15:09:58 檢舉

那請問有類似的方法嗎?
我只是希望在已有的網站也能做普通的flask

froce iT邦大師 1 級 ‧ 2023-01-18 15:20:50 檢舉

不可能利用網頁前端再架個web server啦，安全性問題

froce iT邦大師 1 級 ‧ 2023-01-18 15:30:12 檢舉

另外我實在看不懂你要的是什麼，直接弄個正常的flask做不到嗎？

jton iT邦新手 5 級 ‧ 2023-01-18 15:49:43 檢舉

我做了個補充說明 https://imgur.com/a/spXJAXl，請大大過目

咖咖拉 iT邦好手 1 級 ‧ 2023-01-19 09:02:44 檢舉

PyScript lets you create web apps in Python without the need for a server.
Flask is a Python web app framework for making server-based apps.

你在PyScript 載入 Flask ? ，蠻奇怪的想法XD

froce iT邦大師 1 級 ‧ 2023-01-19 15:08:43 檢舉

https://dormousehole.readthedocs.io/en/latest/deploying/index.html

你要在網際網路上能看到要看這個，不是莫名其妙弄個靜態網頁...

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1 個回答

re.Zero

iT邦研究生 5 級 ‧ 2023-01-18 19:05:18

最佳解答

如果你只是要在網頁內顯示 URL 參數(url-parameters)，可以使用 JavaScript 的 URLSearchParams。

<!DOCTYPE html>
<html>
	<body>
<script type="text/javascript">
const queryString = window.location.search;
const urlParams = new URLSearchParams(queryString);
for (const p of urlParams) {
	document.write(p+'<br/>');
}
</script>
	</body>
</html>