CREATE TABLE XX (
A int,B varchar(10));
INSERT INTO XX
Values(10,'apple'),
(10,'pen'),
(13,'pig'),
(13,'pig'),
(14,'MM');
SELECT A
FROM (
SELECT DISTINCT A,B
FROM XX
) AS YY
GROUP BY A
HAVING COUNT(A)>1
CREATE TABLE [dbo].[_Tmp_0414](
	[idx] [int] IDENTITY(1,1) NOT NULL,
	[A] [nvarchar](10) NULL,
	[B] [nvarchar](10) NULL
) ON [PRIMARY]
GO
  select distinct A
      ,(select distinct B+',' from [_Tmp_0414] where A=t0.A for xml path(''))
          as result      
  from [_Tmp_0414] t0  
A	result
10	apple,pen,
13	pen,
恩~你期望結果是 10
所以是這樣嗎??
declare @Tmp table(
	A nvarchar(50)
	,B nvarchar(50)
)
insert into @Tmp
values('10','apple')
,('10','pen')
,('13','pig')
,('13','pig')
select *
from @Tmp a
group by A,B
having Count(0) = 1
select A
from (
	select *
	from @Tmp a
	group by A,B
	having Count(0) = 1
) k
group by A
