You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction.
If you cannot achieve any profit, return 0
Example 1
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
class Solution:
def maxProfit(self, prices: List[int]) -> int:
n = len(prices)
ans = 0
for i in range(n - 1):
for j in range(i + 1, n):
if prices[j] > prices[i]:
ans = max(ans, prices[j] - prices[i])
return ans
Time Complexity: O(N^2)
Space Complexity: O(1)
class Solution:
def maxProfit(self, prices: List[int]) -> int:
maxProfit = 0
localMin = 0x3f3f3f3f
for v in prices:
localMin = min(localMin, v)
maxProfit = max(maxProfit, v - localMin)
return maxProfit
Time Complexity: O(N)
Space Complexity: O(1)
class Solution:
def maxProfit(self, prices: List[int]) -> int:
n = len(prices)
maxProfit = 0
idxMin = 0
idxMax = 1
while(idxMax < n):
curProfit = prices[idxMax] - prices[idxMin]
if curProfit > 0:
maxProfit = max(maxProfit, curProfit)
else:
idxMin = idxMax
idxMax += 1
return maxProfit
Time Complexity: O(N)
Space Complexity: O(1)
TODO
Time Complexity: O()
Space Complexity: O()