Given a string array words, return an array of all characters that show up in all strings within the words (including duplicates). You may return the answer in any order.
class Solution {
public:
vector<string> commonChars(vector<string>& words) {
vector<int> last = count(words[0]);
for (int i = 1; i < words.size(); i++) {
last = intersection(last, count(words[i]));
}
vector<string> result;
for (int i = 0; i < 26; i++) {
while (last[i] > 0) {
result.push_back(string(1, 'a' + i));
last[i]--;
}
}
return result;
}
private:
vector<int> count(const string& str) {
vector<int> frequency(26, 0);
for (char c : str) {
frequency[c - 'a']++;
}
return frequency;
}
vector<int> intersection(const vector<int>& a, const vector<int>& b) {
vector<int> t(26, 0);
for (int i = 0; i < 26; i++) {
t[i] = min(a[i], b[i]);
}
return t;
}
};